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777dan777 [17]
3 years ago
14

If, according to Newton’s third law, every reaction has an equal and opposite reaction, then how can motion ever occur? Wouldn’t

every force be canceled out by its reaction force?
Physics
2 answers:
shtirl [24]3 years ago
8 0

No, if you push an object, the other side is also "pulling it".

Motion occurs because of the equal and opposite reaction.

timurjin [86]3 years ago
4 0

Motion could not occur if the action force and the reaction force

both acted on the SAME OBJECT.


But they don't. They act on different objects.


The pusher applies the action force to the thing he's pushing, and

the thing he's pushing applies the reaction force to the pusher.


Newton never said that equal and opposite forces cancel out

when they act on two different objects. Only when they act on

the same object.

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Answer:

Number the switches 1, 2 and 3.

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The light that is on is connected to switch 2. The light that is off and warm is connected to switch 1. The light that is off and cold is connected to switch 3!!

Explanation:

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You are given two vectors vector A = 4.9 at 31o vector B = 6 at 156o Angles are measured counterclockwise from the x-axis. What
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Answer:

   C_{y} = 4.96  and     θ' = 104,5º

Explanation:

To add several vectors we can decompose each one of them, perform the sum on each axis, to find the components of the resultant and then find the module and direction.

Let's start by decomposing the two vectors.

Vector A

             sin θ = A_{y} / A

             cos θ = Aₓ / A

             A_{y} = A sin  θ

             Ax = A cos θ

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             Ax = 4.9 cos 31 = 4.20

Vector B

           B_{y} = B sin θ

           Bx = B cos θ

           B_{y} = 6 sin 156 = 2.44

           Bx = 6 cos 156 = -5.48

The components of the resulting vector are

X axis

         Cx = Ax + B x

         Cx = 4.20 -5.48

         Cx = -1.28

Axis y

         C_{y} = Ay + By

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         C_{y} = 4.96

Let's use the Pythagorean theorem to find modulo

         C = √ (Cₙ²x2 + Cy2)

         C = Ra (1.28 2 + 4.96 2)

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We use trigonemetry to find the angle

         tan θ = C_{y} / Cₓ

          θ’ = tan⁻¹ (4.96 / (1.28))

           θ’ = 75.5

como el valor de Cy es positivo y Cx es negativo el angulo este en el segundo cuadrante, por lo cual el angulo medido respecto de eje x positivo es

       θ’ = 180 – tes

        θ‘= 180 – 75,5

        θ' = 104,5º

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Answer:

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