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nikitadnepr [17]
3 years ago
10

An object is transported to three different planets in our solar system. Which of the following is true about that object?

Physics
2 answers:
Digiron [165]3 years ago
8 0

<u>Answer;</u>

<em>D.  The object’s weight changes, but its mass stays the same.</em>

<u>Explanation;</u>

  • Mass is the amount of matter in a object, which is measured in kilograms. Mass of an object is measured using a beam balance. It is important to note that the mass of an object or a body remains constant, and does not vary from one place to another. For instance the mass of a person on the moon will be the same as when the person is on the earth surface.
  • Weight on the other hand is the measurement of gravitational pull of an object. weight is measured using a spring balance and measured in Newtons. Weight varies from one place to another depending on the gravitational pull of a given surface.
kumpel [21]3 years ago
6 0

Yes the answer is D i did the test and got an A.

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An 18-cm-long bicycle crank arm, with a pedal at one end, is attached to a 20-cm-diameter sprocket, the toothed disk around whic
Tpy6a [65]

Answer:

Part a)

a = 0.056 m/s^2

Part b)

L = 7.85 m

Explanation:

Part a)

Angular speed of the pedal is changing from 60 rpm to 90 rpm in 10 s

so the angular acceleration is given as

\alpha = \frac{\omega_2 - \omega_1}{\Delta t}

so we will have

\alpha = \frac{2\pi(\frac{90}{60}) - 2\pi(\frac{60}{60})}{10}

\alpha = 0.314 rad/s^2

now the tangential acceleration of the pedal is given as

a = r \alpha

a = 0.18 \times 0.314

a = 0.056 m/s^2

Part b)

Total angular displacement made by the sprocket in the interval of 10 s is given as

\theta = \frac{\omega_f + \omega_i}{2} t

\theta = \frac{2\pi (\frac{90}{60}) + 2\pi (\frac{60}{60})}{2}(10)

\theta = 78.5 radian

now length of the chain passing over it is given as

L = R\theta

L = 0.10 \times 78.5

L = 7.85 m

6 0
4 years ago
A train is moving with a velocity of 70 km/h.
hodyreva [135]

Answer:

B: It is moving north.

Explanation:

We are told that a train is moving with a velocity of 70 km/h.

Now, we are also told that the positive direction is north.

This means that the train is moving in the northern direction.

We can't say if it is speeding up or not because we are not given the acceleration.

Thus, option B is correct

6 0
3 years ago
A lunar lander is making its descent to moon base i. the lander descends slowly under the retro-thrust of its descent engine. th
olga_2 [115]
V = final velocity
u = initial velocity
a = acceleration
s = displacement
Take downward direction as positive.
v^2 = u^2 + 2as
v^2 = 0.8^2 + 2(1.6)(5.5)
v^2 = 18.24
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5 0
4 years ago
Read 2 more answers
Beginning 156 miles directly east of the city of Uniontown, a truck travels due south. If the truck is travelling at a speed of
timurjin [86]

Answer:

14.3

Explanation:

The distance s as a function of time can be written as:

s(t) = \sqrt{156^{2} + (31t)^2}

The rate of change is the derivative of d with respect to time:

\frac{ds}{dt} =\frac{961t}{\sqrt{156^{2}+(31t)^{2}}}

The time t when the track has been traveling for 81 miles is given by:

81 = 31t\\ t = \frac{81}{31}

Using t in the previous equation gives:

\frac{ds}{dt}(\frac{81}{31} ) =\frac{2511}{\sqrt{156^{2}+81^{2}}}=14.3

5 0
3 years ago
You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh
zhuklara [117]

Complete Question

You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headlights that are 0.681 m apart. At what distance, in kilometres, are you marginally able to discern that there are two headlights rather than a single light source?Take the wavelength of the light to be 549 nm and your pupil diameter as 4.63 mm.  

Answer:

The distance is  z  = 4707.6 \ m

Explanation:

From the question we are told that

    The is distance between the headlight is d = 0.681 \ m

   The wavelength is  \lambda = 549 \ nm = 549 *10^{-9} \ m

    The  pupil diameter is  D  = 4.63 \ mm = 0.00463 \ m

Generally, we can mathematically evaluate the resolution of the eye as

            \theta  = \frac{1.22 *  \lambda }{D}

    substituting values

              \theta  = \frac{1.22 *  549 *10^{-9} }{0.00463}

              \theta  =  (1.45 *10^{-4} )^o

Now according to SOHCAHTOA rule  

         sin \theta  =  \frac{ d}{z}

Where z is  the distance at which the eye can discern the two head light

  given that the angle is very small sin \theta =  \theta

=>    \theta  =  \frac{ d}{z}

substituting values

     1.45*10^{-4}  =  \frac{ 0.681}{z}

=>   z  = \frac{0.681}{1.45 *10^{-4}}

=>    z  = 4707.6 \ m

   

6 0
4 years ago
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