Answer:
2*10^-<em>5</em>
Explanation:
<em>B=</em><em>I</em><em>L</em>
<em>I=</em><em>B</em><em>/</em><em>L</em>
<em>I=</em><em>0</em><em>.</em><em>0</em><em>0</em><em>2</em><em>0</em><em>*</em><em>1</em><em>0</em><em>^</em><em>-</em><em>4</em><em>/</em><em>1</em><em>0</em>
<em>I=</em><em>2</em><em>*</em><em>1</em><em>0</em><em>^</em><em>5</em>
The definition of volocity is <span>the speed of something in a given direction.</span>
Answer:
52,360,000km
Explanation:
To solve this problem you use a conversion factor.
By taking into account that 1UA = 1.496*10^{8}km you obtain:

hence, 0.35UA is about 52,360,000km. This is the least distance between Mars and Earth
Answer:
5.522 m
Explanation:
Data provided:
Mass, m = 1.03 kg
spring constant, k = 861.1 N/m
Distance by which the spring is compressed, x = 0.36
Thus,
the energy stored in the spring = 
on substituting the values, we get
the energy stored in the spring = 
now,
by the conservation of energy, we have
Potential energy gained by the mass = Energy gained by the spring
or
mgh = 
where,
g is the acceleration due to the gravity
h is the maximum height reached by the mass before falling
on substituting the values in the above relation, we get
1.03 × 9.81 × h = 
or
h = 5.522 m