Answer:
Part a)

Part b)

Explanation:
Part a)
Angular speed of the pedal is changing from 60 rpm to 90 rpm in 10 s
so the angular acceleration is given as

so we will have


now the tangential acceleration of the pedal is given as



Part b)
Total angular displacement made by the sprocket in the interval of 10 s is given as



now length of the chain passing over it is given as



Answer:
B: It is moving north.
Explanation:
We are told that a train is moving with a velocity of 70 km/h.
Now, we are also told that the positive direction is north.
This means that the train is moving in the northern direction.
We can't say if it is speeding up or not because we are not given the acceleration.
Thus, option B is correct
V = final velocity
u = initial velocity
a = acceleration
s = displacement
Take downward direction as positive.
v^2 = u^2 + 2as
v^2 = 0.8^2 + 2(1.6)(5.5)
v^2 = 18.24
v = 4.27 m/s
Answer:
14.3
Explanation:
The distance s as a function of time can be written as:

The rate of change is the derivative of d with respect to time:

The time t when the track has been traveling for 81 miles is given by:

Using t in the previous equation gives:

Complete Question
You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headlights that are 0.681 m apart. At what distance, in kilometres, are you marginally able to discern that there are two headlights rather than a single light source?Take the wavelength of the light to be 549 nm and your pupil diameter as 4.63 mm.
Answer:
The distance is 
Explanation:
From the question we are told that
The is distance between the headlight is 
The wavelength is 
The pupil diameter is 
Generally, we can mathematically evaluate the resolution of the eye as

substituting values

Now according to SOHCAHTOA rule

Where z is the distance at which the eye can discern the two head light
given that the angle is very small 
=> 
substituting values

=> 
=> 