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Aleks04 [339]
3 years ago
9

If I have a picosecond laser how would that be expressed in terms of zeptoseconds? In terms of petaseconds?

Physics
1 answer:
kolbaska11 [484]3 years ago
3 0
Picosecond = 10 ^ -12 seconds.
Zeptosecond = 10^ -18 seconsds
Petaseonds  =  10^15  seconds

To express Picoseconds into any of other two, you have to divide  10^-12 by the power index of the one in question

1Picosecond :   10^-12  /  10^-18 =    10^ (-12- 18) =  10^ (-12+18)= 10^6  zeptoseconds

1Picosecond :   10^-12  /  10^15 =    10^ (-12-15) =  10^-27  Petaseconds.

1Picosecond = 10^6  zeptoseconds

1Picosecond = 10^-27  Petaseconds




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What is the distance from axis about which a uniform, balsa-wood sphere will have the same moment of inertia as does a thin-wall
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Answer:

D_{s} ≈ 2.1 R

Explanation:

The moment of inertia of the bodies can be calculated by the equation

     I = ∫ r² dm

For bodies with symmetry this tabulated, the moment of inertia of the center of mass

Sphere               Is_{cm} = 2/5 M R²

Spherical shell   Ic_{cm} = 2/3 M R²

The parallel axes theorem allows us to calculate the moment of inertia with respect to different axes, without knowing the moment of inertia of the center of mass

    I = I_{cm} + M D²

Where M is the mass of the body and D is the distance from the center of mass to the axis of rotation

Let's start with the spherical shell, axis is along a diameter

     D = 2R

    Ic = Ic_{cm} + M D²

    Ic = 2/3 MR² + M (2R)²

    Ic = M R² (2/3 + 4)

    Ic = 14/3 M R²

The sphere

    Is =Is_{cm} + M [D_{s}²

    Is = Ic

    2/5 MR² + M D_{s}² = 14/3 MR²

    D_{s}² = R² (14/3 - 2/5)

    D_{s} = √ (R² (64/15)

    D_{s} = 2,066 R

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3 years ago
Which statement did Ernest Rutherford make about atoms?
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Option A

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A researcher wants to know the effect of lighting on snacking behavior. He knows that young adults normally eat an average of =
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It does not impact snacking behavior.

Explanation:

The mean of the study was 18.7 grams, which is only 2.3 grams below the actual average grams of snacks that an adult would consume while at work, after revising this you could say that theres a significant reduction, but then the standard deviation is 9.1 this means that there are still adults that are eating more than 21 gram of snacks, so the test would result inconclusive.

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2 years ago
How to solve 2.14 using calculus
trasher [3.6K]

Answer:

The acceleration is 6.42\frac{m}{s^2}

Explanation:

Given the velocity function:

v=0.86\frac{m}{s^3}t^2

you can obtain the instantaneous acceleration "a" as its first derivative:

a=\dot{v}=2\cdot0.86\frac{m}{s^3}\cdot t=1.72\frac{m}{s^3}t

To determine the value of "a" when the velocity was 12m/s, you need to figure out the value for "t" when this happens. At what time t is the velocity 12m/s?

12.0\frac{m}{s}=0.86\frac{m}{s^3}t^2\implies t=3.74s

This value of t is less than the 5 seconds mentioned in the text - so that is a good sign that the formula is valid for this value. And so you can use t=3.47s in the derivative (acceleration) above:

a=1.72t=1.72\frac{m}{s^3}\cdot 3.74s = 6.42\frac{m}{s^2}

3 0
3 years ago
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