Answer:
1.60.
Explanation:
- The no. of millimoles of HCl = MV = (0.15 M)(20.0 mL) = 3.0 mmol.
- The no. of millimoles of KOH = MV = (0.10 M)(20.0 mL) = 2.0 mmol.
<em>Since the no. of millimoles of HCl is larger than that of KOH. The solution is acidic.</em>
<em></em>
∴ M of remaining HCl [H⁺] remaining = (NV)HCl - (NV)KOH/V total = (3.0 mmol) - (2.0 mmol) / (40.0 mL) = 0.025 M.
∵ pH = - log[H⁺]
<em>∴ pH = - log[H⁺] </em>= - log(0.025) = <em>1.602 ≅ 1.60.</em>
I would typically assume it is error in the state (s, l, g, aq) but depending on what reaction i couldn't say for sure
Answer:
64cm^3
Explanation:
To get the volume just multiple 4*4*4
Answer:
We produce 2.0 moles of KCl when we have 2.00 moles K and and excess Cl2
Explanation:
Step 1: Data given
Number of moles K = 2.00 moles
Cl2 is in excess, so K is the limiting reactant
Step 2: The balanced equation
2K + Cl2 → 2KCl
Step 3: Calculate moles KCl
For 2 moles K we need 1 mol Cl2 to produce 2 moles KCl
We produce 2.0 moles of KCl when we have 2.00 moles K and and excess Cl2