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sineoko [7]
3 years ago
5

Use implicit differentiation to find y^1 for the equation y^2-y-4x=0

Mathematics
1 answer:
Rudik [331]3 years ago
3 0

Answer:

Step-by-step explanation:

y²-y-4x=0

differentiate w.r.t. x

2y*y^1-y^1-4=0

(2y-1)y^1=4

y^1=4/(2y-1)

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X<br>+ 3 + 5x =<br>I dont know<br>understand<br>this help me​
spin [16.1K]

Answer:

6x + 3

Step-by-step explanation:

Just add the X's (5x + x)=6x, since there is only one whole number without any variables you dont have to do anything to it. So 6x + 3 is your answer.

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JUST ANSWER PLEASE!!! QUICK
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Answer:

<u>Options 1 and 3</u>

Step-by-step explanation:

We should know that, the system of linear equations can be treated as matrices, i.e: we can modify or make any operations provide that we must apply the same operation for all terms of each equation.

Given:  the solution for the following system is (2,9)

Px + Qy = R  ⇒(1)

Tx + Uy = V  ⇒(2)

We will check which system of equation has the same solution.

<u>System A)</u>  Px + Qy = R

                  (P+T)x + (Q+U)y = R+V  ⇒(3)

So, By summing (1) and (2) we will get the equation (3)

So, system A has the same solution (2,9)

<u>System B)</u> Px + Qy = R

                 (P+2T)x + (Q+2U)y = R-2V  ⇒(4)

By multiplying equation (2) by 2 and add with equation (1), we will get:

 (P+2T)x + (Q+2U)y = R+2V

Which is not the same as equation (4)

So, system B has not the same solution (2,9)

<u>System C)</u> (T-P)x + (U-Q)y = V-R  ⇒(5)

                  Tx + Uy = V  

By multiplying equation (1) by -1 and add with equation (2), we will get the equation (5)

So, system C has the same solution of (2,9)

<u>System D)</u> (T-P)x + (Q+U)y = V-R  ⇒(6)

                  Tx + Uy = V  

We cannot get equation (6) by the same operation over equation (1)

Note the coefficient of x and y⇒ (T-P) and (Q+U)

They must be (T+P) and (Q+U) <u>OR </u>(T-P) and (Q-U)

So, system D has not the same solution of (2,9)

<u>System E)</u> (5T-P)x + (5U-Q)y = V-5R ⇒ (6)

                  Tx + Uy = V  

By subtract equation (1) from 5 times equation (2), we will get:

(5T-P)x + (5U-Q)y = 5V-R

Which is not the same as equation (6)

So, system E has not the same solution (2,9)

As a conclusion, the systems which have the same solution are:

<u>Options 1 and 3</u>

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Answer:

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Step-by-step explanation:

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Answer:

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Answer:

Step-by-step explanation:

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