Question

Lim➡️3 (3-x)^2/(x-3)

Answer 1

Answer:

if the limit is three then ans is zero and if limit is -3 then ans is -6

Step-by-step explanation:

it may help you to understand

Answer 2

Answer:

$\boxed{\lim_{x\to 3}\dfrac{(3-x)^2}{(x-3)} =0}$

Step-by-step explanation:

$\lim_{x\to 3}\dfrac{(3-x)^2}{(x-3)}$

$\lim_{x\to 3}\dfrac{(3-x)^2}{-(-x+3)}$

$\lim_{x\to 3}\dfrac{(3-x)(3-x)}{-(-x+3)}$

Cancel the same factor

$\lim_{x\to 3}-(3-x)$

$\lim_{x\to 3}(-3+x)$

Now, once as $x \rightarrow 3$,

$\lim_{x\to 3}(-3+x)=0$