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Contact [7]
4 years ago
14

Is the equation above balanced? How do you know? Mg + 2HCl → MgCl2 + H2

Chemistry
1 answer:
Ede4ka [16]4 years ago
8 0

Answer: The above equation is balanced.

Explanation: Each individual atom are balanced. For Mg it has 1 atom in the reactant and product side. 2 atoms for H and 2 for Cl in both sides.

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Which kingdom does spiny lobster, and diatom belong to?
In-s [12.5K]

Answer:

Animalia

Explanation:

4 0
3 years ago
Answer now pls and i give you mega points ;)
astraxan [27]
HCl is an acid
C5H5N is a base
Cl- is a base
HC5H5N+ is an acid
7 0
3 years ago
A sample of water (88 grams) had a temperature change of 6.0 ℃. What was the heat change of this sample? (q = m c ΔT, c = 4.18 J
jeka94

Answer:

Q=2209J

Explanation:

Hello!

In this case, since the heat involved during a heating process is computed in terms of mass, specific heat and temperature change as shown below:

Q=mC\Delta T

Thus, since the heated mass of water was 88 g, the specific heat of water is 4.184 J/g°C and the temperature change is 6.0 °C, we can compute the heat as shown below:

Q=88g*4.184\frac{J}{g\°C}*6.0\°C \\\\Q=2209J

Best regards!

7 0
3 years ago
(d) What is the mass percentage of water in CdCl2.4H2O?​
Zielflug [23.3K]

The mass percentage of water (H₂O) in cadmium chloride tetra hydratesolution is equal to the 28.2%.

<h3>How do we calculate mass percentage?</h3>

Mass percentage of any substabce present in any solution will be calculated as:
Mass percent = (Mass of substance/Total mass of solution)×100%

According to the question,

Mass of water (H₂O) = 18.02 g/mol

Mass of solvent (CdCl₂.4H₂O) = 183.32 + 4(18.02) = 255.4 g/mol

On putting values, we get

Mass percent = (18.02 / 255.4) × 100% = 28.2%

Hence mass percent of water is 28.2%.

To know more about mass percent, visit the below link:

brainly.com/question/13896694

6 0
2 years ago
Read 2 more answers
A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston wit
Triss [41]

Answer:

The final pressure is approximately 0.78 atm

Explanation:

The original temperature of the gas, T₁ = 263.0 K

The final temperature of the gas, T₂ = 298.0 K

The original volume of the gas, V₁ = 24.0 liters

The final volume of the gas, V₂ = 35.0 liters

The original pressure of the gas, P₁ = 1.00 atm

Let P₂ represent the final pressure, we get;

\dfrac{P_1 \cdot V_1}{T_1} = \dfrac{P_2 \cdot V_2}{T_2}

P_2 = \dfrac{P_1 \cdot V_1 \cdot T_2}{T_1 \cdot V_2}

P_2 = \dfrac{1 \times 24.0 \times 298}{263.0 \times  35.0} = 0.776969038566

∴ The final pressure P₂ ≈ 0.78 atm.

4 0
3 years ago
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