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vladimir1956 [14]
3 years ago
14

Which of the following is an example of a physical property? A. A nail rusting B. Table salt melting C. A camp fire burning D. A

silver spoon tarnishing
Chemistry
2 answers:
Doss [256]3 years ago
6 0

Answer:

a nail rusting

Explanation:

..... .....

galben [10]3 years ago
3 0
A is correct hope this helps
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Solutions are said to be what kind of mixture? A) Pure substance B) Heterogeneous C) Homogenous D) Element
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Solutions are said to be C. homogeneous mixtures, composed of two or more substances. It is usually liquid, however it may be solid or gas.
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What is the net charge of C
sashaice [31]

Explanation:

Sorry, I don't know, but I can tell you that when an atom, or a body, has the same amount of positive charges (protons) and negative charges (electrons), it is said to be electrically neutral. ... The net charge corresponds to the algebraic sum of all the charges that a body possesses.

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2 years ago
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The pattern of inheritance in which more than one pair of genes affects a trait is *
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Answer:

hello, the answer is polygenic:)

8 0
3 years ago
Calculate the pH in titration of a weak acid: What is the pH in titration of formic acid (HCHO2, 0.200 M, 100.0 mL) after the ad
ki77a [65]

Answer:

pH = 12.61

Explanation:

First of all, we determine, the milimoles of base:

0.120 M = mmoles / 300 mL

mmoles = 300 mL . 0120 M = 36 mmoles

Now, we determine the milimoles of acid:

0.200 M = mmoles / 100 mL

mmoles = 100 mL . 0.200M = 20 mmoles

This is the neutralization:

HCOOH    +     OH⁻         ⇄        HCOO⁻     +    H₂O

20 mmol       36 mmol             20 mmol

                    16 mmol

We have an excess of OH⁻, the ones from the NaOH and the ones that formed the salt NaHCOO, because this salt has this hydrolisis:

NaHCOO  →  Na⁺  +  HCOO⁻

HCOO⁻  +  H₂O  ⇄   HCOOH  +  OH⁻   Kb →  Kw / Ka = 5.55×10⁻¹¹

These contribution of OH⁻ to the solution is insignificant because the Kb is very small

So:  [OH⁻] =  16 mmol / 400 mL →  0.04 M

- log  [OH⁻]  = pOH →  1.39

pH = 14 - pOH → 12.61

6 0
3 years ago
10 pts) A student titrates a 20.00 mL sample of an aqueous borax solution with 1.03 M H2SO4. If 2.07 mL of acid are needed to re
Natasha2012 [34]

Answer: The molarity of the borax solution is 0.107 M

Explanation:

The neutralization reaction is:

Na_2B_4O_7.10H_2O+H_2SO_4(aq)\rightarrow Na_2SO_4+4H_3BO_3+5H_2O

According to neutralization law:

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity of H_2SO_4 = 2

n_2 = acidity of borax = 2

M_1 = concentration of H_2SO_4 = 1.03 M

M_2 = concentration of borax =?

V_1 = volume of H_2SO_4  = 2.07ml

V_2 = volume of borax = 20.0 ml

Now put all the given values in the above law, we get the molarity of borax:

(2\times 1.03\times 2.07)=(2\times M_2\times 20.0)

By solving the terms, we get :

M_2=0.107M

Thus the molarity of the borax solution is 0.107 M

7 0
3 years ago
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