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solong [7]
3 years ago
13

What is the momentum of a 3 kg bowling ball moving at 3 m/s?

Physics
1 answer:
nadezda [96]3 years ago
6 0

Answer: 9kgm/s

Explanation:

Given that,

Mass of ball = 3 kg

Speed by which ball moves = 3 m/s. Linear momentum of the ball = ?

Since momentum refers to the quantity of motion of the moving ball,

Linear momentum = Mass x Speed

= 3kg x 3m/s

= 9 kgm/s

Thus, the linear momentum of the ball is 9kgm/s

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Name five characteristics of a star that can be determined by measuring its spectrum. Explain how you would use a spectrum to de
Ne4ueva [31]

Answer:

Chemical composition, Temperature, Radial velocity, Size or diameter of the star, Rotation.

Explanation:  

Elemental abundances are determined by analyzing the relative strengths of the absorption lines in the spectrum of a star.

The Spectral class to which the star belongs gives the information related to the temperature of the star. It is the spectral lines that determine the spectral class O B A F G K M are the spectral classes.

By measuring the wavelengths of the lines in the star's spectrum gives the radial velocity. Doppler shift is the method used to find the radial velocity.

A star can be classified as a giant or a dwarf . A giant star will have narrow width spectral lines whereas a dwarf star has wider spectral lines.

Broadening of the spectral lines will determine the star's rotation.

6 0
3 years ago
16. Two capacitors have an equivalent
Gennadij [26K]

Answer:

C1 + C2 = 30     parallel connection

C1 * C2 / (C1 + C2) = 7.2  series connection

C1 * C2 = 7.2 * (C1 + C2) = 216

C2 + 216 / C2 = 30    using first equation

C2^2 + 216 = 30 C2

C2^2 - 30 C2 + 216 = 0

C2 = 12 or 18    solving the quadratic

Then C1 = 18 or 12

5 0
3 years ago
Which is the pathway for information through a neuron?
Mariulka [41]
Information travels along the axon once an impulse is received. The axon then takes it to the place where it can be sent off to another neuron

<span>dendrite → cell body → axon → axon terminals is the correct answer</span>

<span>If I managed to help you, please make sure to mark my answer as the "Brainliest" answer. Thanks! :)</span>
6 0
3 years ago
Read 2 more answers
A 6.00-kg box sits on a ramp that is inclined at 37.0° above the horizontal. the coefficient of kinetic friction between the box
forsale [732]
We need to see what forces act on the box:

In the x direction:

Fh-Ff-Gsinα=ma, where Fh is the horizontal force that is pulling the box up the incline, Ff is the force of friction, Gsinα is the horizontal component of the gravitational force, m is mass of the box and a is the acceleration of the box.

In the y direction:

N-Gcosα = 0, where N is the force of the ramp and Gcosα is the vertical component of the gravitational force. 

From N-Gcosα=0 we get: 

N=Gcosα, we will need this for the force of friction.

Now to solve for Fh:

Fh=ma + Ff + Gsinα,

Ff=μN=μGcosα, this is the friction force where μ is the coefficient of friction. We put that into the equation for Fh.
G=mg, where m is the mass of the box and g=9.81 m/s²

Fh=ma + μmgcosα+mgsinα

Now we plug in the numbers and get:

Fh=6*3.6 + 0.3*6*9.81*0.8 + 6*9.81*0.6 = 21.6 + 14.1 + 35.3 = 71 N

The horizontal force for pulling the body up the ramp needs to be Fh=71 N.
8 0
3 years ago
Does centripetal force change in uniform circular motion?
HACTEHA [7]
It depends on how fast you are going and in orincipal no
7 0
3 years ago
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