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solong [7]
3 years ago
13

What is the momentum of a 3 kg bowling ball moving at 3 m/s?

Physics
1 answer:
nadezda [96]3 years ago
6 0

Answer: 9kgm/s

Explanation:

Given that,

Mass of ball = 3 kg

Speed by which ball moves = 3 m/s. Linear momentum of the ball = ?

Since momentum refers to the quantity of motion of the moving ball,

Linear momentum = Mass x Speed

= 3kg x 3m/s

= 9 kgm/s

Thus, the linear momentum of the ball is 9kgm/s

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Temperature which is solid becomes a liquid
Brums [2.3K]

Answer:

The answer would be melting point.

Explanation:

Hope this helps. Can you please mark me brainliest

5 0
3 years ago
Read 2 more answers
Lila is a track and field athlete. She must complete four laps around a circular track. The track itself is a 400 meter track an
trapecia [35]

Answer: A. Her speed is 4.4 m/s, and her velocity is 0 m/s.

Explanation: i took the test on edgenuity

6 0
3 years ago
As a way of determining the inductance of a coil used in a research project, a student first connects the coil to a 5.62 V batte
Reptile [31]

Answer:

Its inductance L = 166 mH

Explanation:

Since a current, I = 0.698 A is obtained when a voltage , V = 5.62 V is applied, the resistance of the coil is gotten from V = IR

R = V/I = 5.62/0.698 = 8.052 Ω

Since we have a current of I' = 0.36 A (rms) when a voltage of V' = 35.1 V (rms) is applied, the impedance Z of the coil is gotten from

V₀' = I₀'Z where V₀ = maximum voltage = √2V' and I₀ = maximum current = √2I'

Z = V'/I' = √2 × 35.1 V/√2 × 0.36 V = 97.5 Ω

WE now find the reactance X of the coil from

Z² = X² + R²

X = √(Z² - R²)

= √(97.5² - 8.05²)

= √(9506.25 - 64.8025)

= √9441.4475

= 97.17 Ω

Now, the reactance X = 2πfL where f = frequency of generator = 93.1 Hz and L = inductance of coil.

L = X/2πf

= 97.17/2π(93.1 Hz)

= 97.17 Ω/584.965 rad/s

= 0.166 H

= 166 mH

Its inductance L = 166 mH

5 0
3 years ago
what should be the angle between two vectors of same angle so that their resultant is equal to either of them?​
asambeis [7]

So, the angle between two vectors having equal magnitude is equal to 120º.

Explanation:

<h2>:) Correct me if I'm wrong...</h2>
3 0
2 years ago
If a 0.08 kg cell phone falls off a table at 15 m/s, then what is its kinetic energy right before it hits the ground?
Mariana [72]

The kinetic energy of the phone right before it hits the ground is 9J.

<h3>Kinetic energy of the phone</h3>

The kinetic energy of the phone right before it hits the ground is calculated as follows;

K.E = ¹/₂mv²

where;

  • m is mass of the phone
  • v is velocity of the phone

K.E = ¹/₂(0.08)(15)²

K.E = 9 J

Thus, the kinetic energy of the phone right before it hits the ground is 9J.

Learn more about kinetic energy here: brainly.com/question/25959744

#SPJ1

7 0
2 years ago
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