Answer:
Explanation:
(a) Given data:
Instruction pipeline with 4 phases.
80 instruction
The number of cycles if the processor were pipelined :
80-1 = (79) instruction takes only 1 extra cycle to complete.
So, cycles counts = 4 + (79) = 83 cycles.
The number of cycles if the processor were not pipelined.
Each instruction takes 4 cycles to complete.
So, cycle counts = 80 * 4 = 320 cycles.
(b) One of the main problems of conditional branching in pipelines is the delay it gives even after the branch target buffer.
In pipeline, conditional branches depend on the codes which are still in estimation.
(c) Two ways to deal with problem arising due to conditional branching are as follows :
1. Delayed Branching
2. Multiple Condition Codes
Answer:
Just change your password
Explanation:
go to google account recovery and put in your old username and password if it has been a long time it might not come back. Or you can just change your password
Answer:
- with(open("numbers.txt")) as file:
- data = file.readlines()
- runsum = 0
- largest = 0
-
- for x in data:
- if(int(x) > largest):
- largest = int(x)
- runsum += largest
-
- print(runsum)
Explanation:
The solution code is written in Python 3.
Firstly, open a filestream for numbers.txt (Line 1) and then use readlines method to get every row of data from the text files (Line 2).
Create a variable runsum to hold the running sum of number bigger than the maximum value read up to that iteration in a for loop (Line 3).
Use a for loop to traverse through the read data and then check if the current row of integer is bigger than the maximum value up to that point, set the current integer to largest variable and then add the largest to runsum (Line 6 - 9).
At last display the runsum to console terminal (Line 11).
Answer:
(a) 
= 
Explanation:
To convert from binary to hexadecimal, convert each 4 binary digits to its hexadecimal equivalent according to the following;
<em>Binary => Hex</em>
0000 => 0
0001 => 1
0010 => 2
0011 => 3
0100 => 4
0101 => 5
0110 => 6
0111 => 7
1000 => 8
1001 => 9
1010 => A
1011 => B
1100 => C
1101 => D
1110 => E
1111 => F
(a) 1100 1111 0101 0111
=> Taking the first four binary digits : 1100
According to the table, the hexadecimal equivalent is C
=> Taking the second four binary digits : 1111
According to the table, the hexadecimal equivalent is F
=> Taking the third four binary digits : 0101
According to the table, the hexadecimal equivalent is 5
=> Taking the last four binary digits : 0111
According to the table, the hexadecimal equivalent is 7
Therefore, the hexadecimal representation of
1100 1111 0101 0111 is CF57
