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Rainbow [258]
3 years ago
13

When 8.0 grams of sodium hydroxide is dissolved in sufficient water to make 400. mL of solution, what is the concentration of th

e solution?
Chemistry
1 answer:
nata0808 [166]3 years ago
6 0

Answer:

The concentration of this sodiumhydroxide solutions is 0.50 M

Explanation:

Step 1: Data given

Mass of sodium hydroxide (NaOh) = 8.0 grams

Molar mass of sodium hydroxide = 40.0 g/mol

Volume water = 400 mL  = 0.400 L

Step 2: Calculate moles NaOH

Moles NaOH = mass NaOH / molar mass NaOH

Moles NaOH = 8.0 grams / 40.0 g/mol

Moles NaOh = 0.20 moles

Step 3: Calculate concentration of the solution

Concentration solution = moles NaOH / volume water

Concentration solution = 0.20 moles / 0.400 L

Concentration solution = 0.50 M

The concentration of this sodiumhydroxide solutions is 0.50 M

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<span>an electrolytic cell</span>
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How many total moles of ions are released when the following sample dissolves completely in water? Enter your answer in scientif
levacccp [35]

Answer:

Total moles of ions are released in water are 1.131\times 10^{-5} mol.

Explanation:

Mass of calcium nitrate = 6.18\times 10^{-4} g

Molar mass of calcium nitrate = 164 g/mol

Moles of calcium nitrate = \frac{6.18\times 10^{-4} g}{164 g/mol}=3.77\times 10^{-6} mol

Ca(NO_3)_2(aq)\rightarrow Ca^{2+}(aq)+2NO_3^{-}(aq)

According to reaction, 1 mole of calcium nitrate gives 1 mole of calcium ions, then 3.77\times 10^{-6} moles of calcium nitrate will give:

1\times 3.77\times 10^{-6} mol=3.77\times 10^{-6} mol of calcium ions

According to reaction, 1 mole of calcium nitrate gives 2 mole of nitrate ions, then 3.77\times 10^{-6} moles of calcium nitrate will give:

2\times 3.77\times 10^{-6} mol=7.54\times 10^{-6} mol of nitrate ions

Total moles of ions are released :

3.77\times 10^{-6} mol+7.54\times 10^{-6} mol=11.31\times 10^{-6} mol\approx 1.131\times 10^{-5} mol

6 0
3 years ago
If 0.905 mol Al2O3 is produced in the reaction, what mass of Fe in product's
Marrrta [24]

<u>Answer:</u> Amount of iron produced is 101.36 grams.

<u>Explanation:</u>

For the reaction of aluminium and iron oxide, the equation follows:

2Al+Fe_2O_3\rightarrow Al_2O_3+2Fe

By Stoichiometry of the reaction,

When 1 mole of aluminium oxide is produced, then 2 moles of iron is also produced.

So, when 0.905 moles of aluminium oxide is produced, then \frac{ 2}{1}\times 0.905mol=1.81moles of iron is also produced.

Now, to calculate the amount of iron produced, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of iron = 56 g/mol

Moles of iron = 1.81 moles

Putting values in above equation, we get:

1.81mol=\frac{\text{Mass of iron}}{56g/mol}\\\\\text{Mass of iron produced}=101.36g

Hence, amount of iron produced is 101.36 grams.

3 0
3 years ago
In a reversible reaction, the endothermic reaction absorbs ____________ the exothermic reaction releases. A. less energy than B.
Alex Ar [27]

Answer: C. the same amount of energy as

Explanation:

A reversible reaction is a chemical reaction where the reactants form products that, in turn, react together to give the reactants back.

Reversible reactions will reach an equilibrium point where the concentrations of the reactants and products will no longer change.

A+B\rightleftharpoons C+D

Thus if forward reaction is exothermic i.e. the heat is released , the backward reaction will be endothermic i.e. the heat is absorbed and in same amount.

The amount of energy released will be equal and opposite in sign to the energy absorbed in that reaction.

5 0
3 years ago
Chlorine has two natural isotopes, chlorine-35 and chlorine-37.
Alex Ar [27]

Answer:

The relative atomic mass of chlorine depends on the ratio between the abundance of these two naturally-occurring isotopes.

Explanation:

The relative atomic mass of an element is a weighted average of the atomic mass of its naturally-occurring isotopes. The relative abundance of each isotope gives its weight in this weighted average.

For these two naturally-occurring isotopes of chlorine:

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  • The relative atomic mass ^{37}{\rm Cl} is approximately 36.966 daltons. The relative abundance of this isotope in nature is approximately 0.242.

\begin{array}{|c|c|c|}\cline{1-3} \text{Isotope} & \text{Atomic Mass} & \text{Relative Abundance}\\ \cline{1-3} ^{35}{\rm Cl} & \approx 34.968\; \rm Da} & \approx 0.758 \\ \cline{1-3} ^{37}{\rm Cl} & \approx 36.966\; \rm Da & \approx 0.242 \\ \cline{1-3}\end{array}.

\begin{aligned}&\text{relative atomic mass of Cl} \\ &= \text{atomic mass of $^{35}{\rm Cl}$} \times \text{relative abundance of $^{35}{\rm Cl}$} \\&\quad + \text{atomic mass of $^{37}{\rm Cl}$} \times \text{relative abundance of $^{37}{\rm Cl}$} \\ &\approx 34.968\; \rm Da \times 0.758 + 36.966\; \rm Da \times 0.242 \\ &\approx 35.45\; \rm Da \end{aligned}.

The relative abundance of ^{35}{\rm Cl} is much higher than that of ^{37}{\rm Cl}. Consequently, the relative atomic mass of the element \rm Cl is closer to the atomic mass of ^{35}{\rm Cl}\! than that of ^{37}{\rm Cl}\!.

7 0
3 years ago
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