Answer:
His average speed is 0.15 kilometer per minute or 2.5 meters per second.
Explanation:
average speed = distance/time
x = 3 km/20 minutes
x = 0.15
—
x = 3000 m/1200 s
x = 2.5
Answer:
I had the same question a while ago !
Explanation:
Um u need to show what the options are.
Say the horizontal component of the velocity is vx and the vertical is vy.
Initially at t=0 (as the mug leaves the bar) the components are v0x and v0y.
Obviously (I hope!) v0y = 0.
The equations for horizontal and vertical projectile motion (with the positive direction up) are
x = x0 + v0x t
y = y0 + v0y t - 1/2 g t^2 = y0 - 1/2 g t^2
Now choose the origin to be the end of the counter. x0=0 and y0=0. The equations simplify to
x = v0x t
y = - 1/2 g t^2
You know that x = 1.20m when y = -0.88m
From the y equation (and g=10 m/s^2) you can calculate the time that the mug hits the floor.
t = 0.420s
From the x equation we get the initial horizontal velocity
v0x = x/t = 1.2/0.42 = 2.86 m/s
(b) x-component of velocity is constant since there are no horizontal forces so vx = 2.86 m/s
y-component is given by v = u+at with u=0 and a=-g
vy = -gt = -4.2m/s
Now tan(angle) = vy/vx so angle = arctan(vy/vx)