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Novosadov [1.4K]
3 years ago
6

Which of the follbwing ways of coping with emotions is helpful?

Physics
2 answers:
____ [38]3 years ago
8 0
D is the correct answer
defon3 years ago
6 0

Answer:

Confronting the situation head on.

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3. What is the acceleration of a 10 kg mass pushed by a 5 N force?
insens350 [35]

Answer:

F=ma

Plug it in:

5=10a

5/10=(10a)/10

.5m/s²=a

Explanation:

Brainliest?

5 0
3 years ago
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Find the equation of the line below.
Musya8 [376]

Answers all in picture below

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7 0
3 years ago
What is the kinetic energy of a 74.0 kg skydiver falling at a terminal velocity of 52.0m/s?
skad [1K]

Answer:

100,048

Explanation:

K.E = 1/2 m (v)^2

K.E = 1^/2 * 74 * (52)^2

K.E = 100,048J =100.048kJ

8 0
3 years ago
how does gravity affect objects of different mass close to earth, and how does that effect change as an object moves farther fro
Luda [366]

Answer:

It makes it lighter when its closer and heavier when its farther way.

Explanation:

3 0
2 years ago
An object of mass 2.0 kg is attached to the top of a vertical spring that is anchored to the floor. The unstressed length of the
poizon [28]

Answer:

The value is A  =  0.014 \  m

Explanation:

From the question we are told that

    The mass of the object is  m  =  2.0 \  kg

    The unstressed length of the string is  l  =  0.08 \  m

    The length of the spring when it is  at equilibrium is  l_e = 5.9 \  cm  =  0.059 \  m

      The initial speed (maximum speed)of the spring when given a downward blow v  =  0.30 \  m/s

Generally the maximum speed  of the spring  is mathematically represented as

           u =  A *  w

Here A is maximum height above the floor (i.e the maximum amplitude)

            and w is the angular frequency which is mathematically represented as

       w = \sqrt{\frac{k}{m} }

So

        u =  A *   \sqrt{\frac{k}{m} }

=>      A  =  u *   \sqrt{\frac{m}{k} }

Gnerally the length of the compression(Here an assumption that the spring was compressed to the ground by the hammer is made) by the hammer is mathematically represented as

           b  =  l -l_e

=>         b  = 0.08 - 0.05 9

=>         b  = 0.021 \  m

Generally at equilibrium position the net force acting on the spring is  

            k *  b  -  mg  =  0

=>         k *  0.021   -   2 * 9.8  =  0

=>        k =  933 \  N/m

So

            A  =  0.30  *   \sqrt{\frac{2}{933} }

=>          A  =  0.014 \  m

8 0
2 years ago
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