Answer:
Explanation:
Coulomb's law states that the force of attraction or repulsion between any two charges is proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between the charges
⇒
∴
where 
is the force of attraction or repulsion
is Coulumb's constant=
and 
are the magnitude of the charges
is the distance between two charges
The force between the two charges is attractive if they are of different polarity
The force between the two charges is repulsive if they are of same polarity
Question 7:
Given: 
, 
By coulomb's law,
⇒
Question 6:
Given: 
, 
By coulomb's law,
⇒
Answer:
2.5 m/s²
Explanation:
You can solve the following equation: F=ma for acceleration.
You'll be left with this:
a=F/m
And then you substitute the force and the doubled mass
a=500N/200kg
a=2.5 m/s²
<u>Answer:</u>
Pressure exerted = 500 Pa
<u>Explanation:</u>
The formula for pressure is as follows:
In this case,
Force applied = 100N
Area = 40cm × 50cm = 2000cm² = 2000 × 10⁻⁴ = 0.2m²
Substituting these values into the formula:
Pressure = 
⇒ Pressure = 500 Pa
The wavelength and frequency of light are closely related. The higher the frequency, the shorter the wavelength. Because all light waves move through a vacuum at the same speed, the number of wave crests passing by a given point in one second depends on the wavelength. That number, also known as the frequency, will be larger for a short-wavelength wave than for a long-wavelength wave.
Answer:
-4×-2y=14 (1)
-10×+7y=-25 (2)
multiplying eq 1 by 7 and eq 2 by 2 and add eq. 1 and 2
-28×-14y=98
-20×+14y=-50
___________
-28×=48
×=48/-28
×=-12/7
now
-4×-2y=14
-4*-12/7-2y=14
48/7-2y=14
-2y=14-48/7
-2y=(98-48)/7
-2y=50/7
y=-50/14
y=-25/7
