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balandron [24]
3 years ago
6

The temperature of coffee served at a restaurant is normally distributed with an average temperature of 160 degrees Fahrenheit a

nd a standard deviation of 5.4 degrees Fahrenheit. What is the coffee temperature for the 20th percentile? Enter your answer to four decimal places.
Mathematics
1 answer:
posledela3 years ago
7 0

Answer:

The 20th percentile of coffee temperature is 155.4532 degrees Fahrenheit.  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 160 degrees

Standard Deviation, σ = 5.4 degrees

We are given that the distribution of temperature of coffee is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.2

P( X < x) = P( z < \displaystyle\frac{x - 160}{5.4})=0.2  

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 160}{5.4} = -0.842\\\\x = 155.4532  

Thus,

P_{20}=155.4532

The 20th percentile of coffee temperature is 155.4532 degrees Fahrenheit.

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The intersection point is only one. Then the equation of the line is tangent to the circle at point (1, -2).

<h3>What is a circle?</h3>

It is a locus of a point drawn an equidistant from the center. The distance from the center to the circumference is called the radius of the circle.

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Then from equations 1 and 2, we have

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