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balandron [24]
3 years ago
6

The temperature of coffee served at a restaurant is normally distributed with an average temperature of 160 degrees Fahrenheit a

nd a standard deviation of 5.4 degrees Fahrenheit. What is the coffee temperature for the 20th percentile? Enter your answer to four decimal places.
Mathematics
1 answer:
posledela3 years ago
7 0

Answer:

The 20th percentile of coffee temperature is 155.4532 degrees Fahrenheit.  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 160 degrees

Standard Deviation, σ = 5.4 degrees

We are given that the distribution of temperature of coffee is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.2

P( X < x) = P( z < \displaystyle\frac{x - 160}{5.4})=0.2  

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 160}{5.4} = -0.842\\\\x = 155.4532  

Thus,

P_{20}=155.4532

The 20th percentile of coffee temperature is 155.4532 degrees Fahrenheit.

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The missing coordinates of the parallelogram is (m + h, n).

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Diagonals of the parallelogram bisect each other.

Solve using mid-point formula:

$\text{Midpoint} =\left( \frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right  )

Here x_1=m, y_1=n, x_2=h, y_2=0

              $=\left( \frac{m+h}{2}, \frac{n+0}{2}\right  )

$\text{Midpoint} =\left( \frac{m+h}{2}, \frac{n}{2}\right  )

<u>To find the missing coordinate:</u>

Let the missing coordinates by x and y.

Here x_1=0, y_1=0, x_2=x,  y_2=y

$\text{Midpoint}=\left( \frac{0+x}{2}, \frac{0+y}{2}\right  )

$\left( \frac{m+h}{2}, \frac{n}{2}\right  )=\left( \frac{0+x}{2}, \frac{0+y}{2}\right  )

$\left( \frac{m+h}{2}, \frac{n}{2}\right  )=\left( \frac{x}{2}, \frac{y}{2}\right  )

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$\frac{n}{2} =  \frac{y}{2}

Multiply by 2 on both sides of the equation, we get

n = y

y = n

Hence the missing coordinates of the parallelogram is (m + h, n).

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