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kap26 [50]
3 years ago
12

Use the periodic to write the electron configuration for rubidium (Rb) in noble-gas notation. . Rb: [Kr]s

Chemistry
2 answers:
Mashcka [7]3 years ago
6 0

Answer:

the answer is 5

Explanation:

gladu [14]3 years ago
5 0

Answer:-

[Kr] 5s1

Explanation:-

Atomic number of rubidium = 37

Atomic number of Kr = 36

So only 1 electron needs to be assigned an orbital.

Kr is also the last element of the fourth period

So the shell number for the 1 electron will be 5 since it is after Kr

Since s subshell is filled first the electron will go into 5s.

Hence the electron configuration for rubidium (Rb) in noble-gas notation is

[Kr] 5s1

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Answer:

1,085g of water

Explanation:

If we have the value 4520kj is because the question is related to Energy and heat capacity. In this case, the law and equation that we use is the following:

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m is the mas

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In order to determine the mass, I will have the same equation but finding m

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3 years ago
Both E. coli and Salmonella are single-celled organisms. They do not have a nucleus or other membrane-bound organelles. Based on
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7 0
3 years ago
What is the total number of moles (n) of electrons exchanged between the oxidizing agent and the reducing agent in the overall r
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Explanation:

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<span>                   5 Ag</span>⁺ + Mn⁺²<span> + 4 H</span>₂O    →<span>    5 Ag + MnO</span>₄⁻<span> + 8 H</span>⁺

Reduction of Ag:

                         Ag⁺ + 1 e⁻    →    Ag
Or,
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                          Mn⁺²   →    MnO₄⁻  +  5 e⁻

Result:
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