The net force acting on the airplane is 25N.
Forces acting on the paper airplane when it is in the air:
- The forward force generated by the engine, propeller, or rotor is called thrust. It resists or defeats the drag force. It operates generally perpendicular to the longitudinal axis. However, as will be discussed later, this is not always the case.
- Drag is an airflow disruption generated by the wing, rotor, fuselage, and other projecting surfaces that causes a backward, decelerating force. Drag acts backward and perpendicular to the relative wind, opposing thrust.
- Weight is the total load carried by airplane, including the weight of the crew, fuel, and any cargo or baggage. Due to the influence of gravity, weight pulls the airplane downward.
- Lift—acts perpendicular to the flight path through the center of lift and opposes the weight's downward force. It is produced by the air's dynamic influence on the airfoil.
Given.
Weight of the paper airplane, F1 = 16N
The force of air resistance, F2 = 9N
Net force = F1 + F2
Net force = 25N
Thus, the net force acting on the airplane is 25N.
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Answer:
The force of the car engine.
Explanation:
The work- energy theorem states that the work done on an object is equal to the change in its kinetic energy. Its expression is given by :
Also, W = F.d
Where
F is the force applied by the engine of car
d is the displacement
m is the mass of an object
u is the initial speed
v is the final speed
So, the force of the car engine increased the car’s kinetic energy. Hence, this is the required solution.
Answer:
11.72 m/s
Explanation:
Energy is conserved when there are no energy loses. So potential energy and kinetic energy must be the same at the beginning and at the end.
Mechanical energy is the addition of both energy types, which is conserved.
So E= P+ K,
E: Mechanical energy
P: Potential Energy
K: kinetic energy.
P= m*g*h
K= (m*v^2)/2
M:mass
G:gravity=9.8m/s^2
H:altitude=7m
V: Velocity.
So P+K is conserved,
P1+K1=P2+K2
At the beginning there's no movement, so V=0, then K1=0
At the end there's no altitude, so H=0, then P2=0.
For those reasons,
P1=K2
M*G*H= M*v^2*0.5. As M is in both sides, we can take it out, and replace gravity and altitude with the values we already have.
9,81(m/s^2)* 7m = v^2 *0.5
68.67 (m/s)^2 = v^2 *0.5
(68.67 (m/s)^2 :0.5) ^ (1/2)= |v|
137.34^0.5=|v|
11.72 m/s= |v|
The sign will depend on where are we considering the 0 so will it be positive velocity if it's increasing direction or negative if it is decreasing
Assuming Adam is on earth g= 9.8 m/s and m= weight/ gravity = 667/9.8 = 68 kg
Explanation:
acceleration is rate of change in velocty
v = 24 - 13 = 11km/hr = 3.06m/s
a = 3.06/2 = 1.53 m/s^2
