<span> B. A person moving a ball through a stream of water</span>
Answer:
The change in momentum is
Explanation:
From the question we are told that
The mass of the probe is ![m = 170 kg](https://tex.z-dn.net/?f=m%20%3D%20170%20kg)
The location of the prob at time t = 22.9 s is ![A =](https://tex.z-dn.net/?f=A%20%20%3D%20%3C5600%2C%207200%2C0%3E)
The momentum at time t = 22.9 s is
The net force on the probe is ![F = N](https://tex.z-dn.net/?f=F%20%3D%20%3C-4000%20%2C%20-780%20%2C%200%3E%20N)
Generally the change in momentum is mathematically represented as
![\Delta p = F * \Delta t](https://tex.z-dn.net/?f=%5CDelta%20p%20%3D%20F%20%2A%20%5CDelta%20t)
The initial time is 22.6 s
The final time is 22.9 s
Substituting values
![\Delta p = * (22.9 - 22.6)](https://tex.z-dn.net/?f=%5CDelta%20p%20%3D%20%3C-4000%20%2C%20-780%20%2C%200%3E%20%2A%20%2822.9%20-%2022.6%29)
Coal is burned to get energy. By burning coal, green houses gases like carbon dioxide, nitrogen oxides and suphur oxides are produced.
Rest of the energy sources given in the option are clean energies.
Answer is A.
Answer:
![Q = 4.63 \times 10^6 J](https://tex.z-dn.net/?f=Q%20%3D%204.63%20%5Ctimes%2010%5E6%20J)
Explanation:
As we know that melting point of silver is
T = 961.8 degree C
Latent heat of fusion of silver is given as
L = 111 kJ/kg
specific heat capacity of silver is given as
![s = 240 J/kg C](https://tex.z-dn.net/?f=s%20%3D%20240%20J%2Fkg%20C)
now we will have
![Q = ms\Delta T + mL](https://tex.z-dn.net/?f=Q%20%3D%20ms%5CDelta%20T%20%2B%20mL)
![\Delta T = 961.8 - 20](https://tex.z-dn.net/?f=%5CDelta%20T%20%3D%20961.8%20-%2020%20)
![\Delta T = 941.8 degree C](https://tex.z-dn.net/?f=%5CDelta%20T%20%3D%20941.8%20degree%20C)
now from above equation
![Q = (13.74)(240)(941.8) + (13.74)(111 \times 10^3)](https://tex.z-dn.net/?f=Q%20%3D%20%2813.74%29%28240%29%28941.8%29%20%2B%20%2813.74%29%28111%20%5Ctimes%2010%5E3%29)
![Q = 3.1 \times 10^6 + 1.53 \times 10^6](https://tex.z-dn.net/?f=Q%20%3D%203.1%20%5Ctimes%2010%5E6%20%2B%201.53%20%5Ctimes%2010%5E6)
![Q = 4.63 \times 10^6 J](https://tex.z-dn.net/?f=Q%20%3D%204.63%20%5Ctimes%2010%5E6%20J)