2 years ago

For each system of equations, drag the true statement about its solution set to

1 answer:

7 0

The first one is zero solution because 6x+3 will never be 6x-3 and the second one is one soupy toon because 6x+3=2x+1 equals one solution

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Write and equivalent exspression to 8k-(5+2k) without parentheses then simplify

Nezavi [6.7K]

Answer:

6k - 5

Step-by-step explanation:

8k-(5+2k)

8k -5 -2k

6k - 5

3 0

3 years ago

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Rewrite, using the distributive property 7(3z + 12) = [?]z + [|]

luda_lava [24]

Answer:

21z+84

Step-by-step explanation.

7x3=21 then put the z at the end 21z.

7x12=84. Put it after the 21z. 21z+84

3 0

2 years ago

Solve the equation below for y. 5/6y = 12

mestny [16]

The answer is 5/72 you would just divide 5/6 by 12 hope this helped

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3 years ago

Which answer best describes the complex zeros of the polynomial function?

marysya [2.9K]

Answer-

D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.

Solution-

The given polynomial is,

$f(x)=x^3-x^2+6x-6$

The zeros of the polynomials are,

$\Rightarrow f(x)=0$

$\Rightarrow x^3-x^2+6x-6=0$

$\Rightarrow x^2(x-1)+6(x-1)=0$

$\Rightarrow (x^2+6)(x-1)=0$

$\Rightarrow (x^2+6)=0,(x-1)=0$

$\Rightarrow x=\sqrt{-6},\ x=1$

$\Rightarrow x=1,\ \pm \sqrt6i$

Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1

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3 years ago

What is the standard form of (7-5i)(2+3i)? A.-29+11i B.29+11i C. 11-29i D.-11+29i

Lubov Fominskaja [6]

It might be the last one but I don't know

5 0

2 years ago

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