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2 years ago

For each system of equations, drag the true statement about its solution set to

Mathematics

1 answer:

Bess [88]2 years ago

7 0

The first one is zero solution because 6x+3 will never be 6x-3 and the second one is one soupy toon because 6x+3=2x+1 equals one solution

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Write an inequality for the graph below

andrezito [222]

Answer:

y > -1/4x + 4

Step-by-step explanation:

First find the equation of the line itself, which is y = -1/4x + 4, then determine if graph shades above the line or below the line. If it shades above which is true in this case, it will be greater than. If it shades below which does not occur in this case, it will be less than. Because the line is dashed and not solid, it will just be greater than or less than.

Therefore y = -1/4x + 4 → y > -1/4x + 4 [Shades above the line, line is dashed].

6 0

1 year ago

The third term is given 2 and the sixth term is 15 . find the first term and the common ratio .

Mumz [18]

Answer:

Answer to your query is provided below in the image attached

8 0

2 years ago

Ann has 30% less money than Mary, and Jessica has 70% more than Mary. If the 3 of them have a (added up) total of $102, how much

Roman55 [17]

Let x be the amount of Ann money, y be Jessica's money and z Mary money.
30% of z equates 0.3*z.
Ann has 30% less than z so: x = z - 0.3z = 0.7z.
70% of z equates 0.7z.
"Jessica has 70% more than Mary " we deduce the equation: y =z+0.7z= 1.7z.
Signe the total is $102, we deduce the equation x+y+z = 102.
x=0.7z and y=1.7z then 0.7z+1.7z+z=102, therefore 3.4z=102 then
z =102/3.4 = $30.
x=0.7*30= 21 and y=1.7*30=51.

Ann has $21, Mary has $30 and Jessica has $51.

3 0

2 years ago

2 dogs/ 3 cats and 10 dogs/ 15 cats are an example of

Bad White [126]

2 dogs/ 3 cats and 10 dogs/ 15 cats are an example of

b. Equivalent ratios
__________________________

$\frac{10 \: dogs}{15 \: cats} = \frac{5 \times 2 \: dogs}{ 5 \times 3 \: cats} = \frac{2 \: dogs}{3 \: cats} \\$

We can see that they are equivalent ratios.

6 0

2 years ago

The depth of a lake in cedar burg changes over time due to rain fall and evaporation this year it was 39 feet which is 25% less

Nostrana [21]

Answer:

The depth of the lake last year was 52 feet

Step-by-step explanation:

Given as :

This year depth of lake = 39 feet

Let the last year depth of lake = x feet

Now,

According to question :

The depth this year is 25% less than that of last year

I.e 39 feet = x - 25% of x

Or, 39 feet = $\frac{75x}{100}$

or, x = $\frac{3900}{75}$

∴ x = 52 feet

Hence The depth of the lake last year was 52 feet Answer

4 0

2 years ago