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bixtya [17]
3 years ago
14

One seed was planted in each of 5 pots found around the house that contained 500g of "Pete`s potting Soil." The pots were given

the following amounts of distilled water each day for each day of 40 days: pot 1, 50mL; Pot 2, 100mL; Pot 3, 150mL; Pot 4, 200mL; Pot 5, 250mL. Because Pot 3 received the recommended amount of water it was used as a control. The height of each plant was measured at the end of the experiment. What is the independent variable?
Biology
1 answer:
riadik2000 [5.3K]3 years ago
8 0

Answer:

The independent variable is amounts of distilled water.

Explanation:

The dependent variable of this experiment is the height of each plant which is dependent on the amounts of distilled water added to each pot. Notice that days and amount of soil are constants. Therefore, the independent variable in this case is the amount of water added to each pot.

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Answer:

Fraction-of-occurrences of 115In isotope = 0.957

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As we know  weight of 113 In  isotope is equal to the sum of product of fraction-of-occurrences of two constituents isotopes and their atomic weight

^{115}In_w = f_{113}*A_{113} + f_{115}*A_{115} ------(1)

As we know sum of fraction-of-occurrences of two constituents isotopes is equal to one.

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Substituting the given values in equation 1, we get

^{115}In_w = f_{113}*A_{113} + f_{115}*A_{115}\\114.818 = (1 - f_{115}) * 112.904 + f_{115} * 114.904\\f_{115} = 0.957

Substituting this value in equation 2 we get -

f_{113} = 1- f_{115}\\f_{113} =  1- 0.957 \\f_{113} = 0.043

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