Answer:
I finish that module I'm sure it's D
I<span>the rounded Atomic mass of iron</span>ron is
- Fe : 55.85,
<span>0.506 m/s^2
Given the arrangement of rope and the man, he's effectively suspended by a rope from a frictionless pulley. So he's pulling the rope with a force of 371 n causing him to be pulled upwards by his arms. Additionally, the rope goes up to the pulley and back down to the man causing an additional 371 n of force pulling him upwards. So the total force being used to lift the man is 742 n.
Additionally, the man is being pulled downwards by gravity at 9.80 m/s^2. And since he masses 72.0 kg, the downward force in newtons is 72.0 kg * 9.80 m/s^2 = 705.6 n downward.
So the total force being exerted on the man is
742 n - 705.6 n = 36.4 n
To calculate his acceleration, simply divide the number of newtons applied by his mass.
36.4 kg m/s^2 / 72.0 kg = 0.505556 m/s^2
And round to 3 significant figures.
0.505556 m/s^2 = 0.506 m/s^2</span>
Answer:
C) The lander’s velocity decrease toward the reference.
Explanation:
took the test
Answer:
480.2 m
Explanation:
The following data were obtained from the question:
Speed of sound (v) = 343 m/s.
Time (t) = 2.8 s
Distance (x) of the cliff =?
The distance of the cliff from the woman can be obtained as follow:
v = 2x /t
343 = 2x /2.8
Cross multiply
2x = 343 × 2.8
2x = 960.4
Divide both side by the coefficient of x i.e 2
x = 960.4/2
x = 480.2 m
Therefore, the cliff is 480.2 m away from the woman.
