Answer:
The range of angles is from 17.50° to 31.76°
Explanation:
The diffraction grid equation is as follows:

Clearing for 


where
is the angle,
is the order, in this case
,
is the wavelength, and
is defined as follows:

and since the resolution is 750 lines/mm wich is the same as 
will be:

wich is the distance between each line of the diffraction grating.
substituting the values for
and
:

And we need to find two angle values: one for when the wavelength is 400nm and one for when it is 700 nm. So we will get the angle range

and

The range of angles is from 17.50° to 31.76°
Electronegativity<span> is a relative measure of how strongly an atom </span>will<span> attract the electrons in a bond</span>
I have the same thing for homework
Answer:
magnitude: 21.6; direction: 33.7 degrees
Explanation:
When we multiply a vector by a scalar, we have to multiply each component of the vector by the scalar number. In this case, we have
vector: (-3,-2)
Scalar: -6
so the vector multiplied by the scalar will have components

The magnitude is given by Pythagorean's theorem:

and the direction is given by the arctan of the ratio between the y-component and the x-component:
