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Arlecino [84]
3 years ago
11

What is the Percent yield made if 3.9 grams of a substance were made experimentally while you calculated 3.6 grams of substance

using Stoichiometry?
Chemistry
1 answer:
son4ous [18]3 years ago
8 0

Answer:

108.3%

Explanation:

Percent yield is the concept where you calculate the ratio or percent of actual yield to theoretical yield.

Actual yield is what you actually experimentally got.

Theoretical yield is what you expected to get from math.

Always remember the two terms above will never be same in real life because we do not have perfect system where we can account for energy loss and such in daily life.

Percent yield= actual yield/theoretical yield  x 100%

                    =  3.9/3.6 x 100%

                     = 108.3%

Percent yields are understandably less than 100% because of the reasons indicated earlier like imperfect systems. However, percent yields greater than 100% are possible, such as our question, if the measured product of the reaction contains impurities that cause its mass to be greater than it actually would be if the product was pure.

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What is the empirical formula for the following molecular formula: C10H5O2
Tju [1.3M]

The empirical formula is the same as the molecular formula : C₁₀H₅O₂

<h3>Further explanation</h3>

Given

Molecular formula : C₁₀H₅O₂

Required

The empirical formula

Solution

The empirical formula (EF) is the smallest comparison of atoms of compound forming elements.  

The molecular formula (MF) is a formula that shows the number of atomic elements that make up a compound.  

(empirical formula) n = molecular formula  

<em>(EF)n=MF </em>

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If we divide by the number of moles of Oxygen (the smallest) which is 2 then the moles of Hydrogen will be a decimal number (not whole), which is 2.5, then the empirical formula is the same as the molecular formula

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EXPERIMENT: THE CABBAGE INDICATOR
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Answer:

EXPERIMENT: THE CABBAGE INDICATOR

Here are your goals for this lesson:

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Explanation:

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