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Arlecino [84]
3 years ago
11

What is the Percent yield made if 3.9 grams of a substance were made experimentally while you calculated 3.6 grams of substance

using Stoichiometry?
Chemistry
1 answer:
son4ous [18]3 years ago
8 0

Answer:

108.3%

Explanation:

Percent yield is the concept where you calculate the ratio or percent of actual yield to theoretical yield.

Actual yield is what you actually experimentally got.

Theoretical yield is what you expected to get from math.

Always remember the two terms above will never be same in real life because we do not have perfect system where we can account for energy loss and such in daily life.

Percent yield= actual yield/theoretical yield  x 100%

                    =  3.9/3.6 x 100%

                     = 108.3%

Percent yields are understandably less than 100% because of the reasons indicated earlier like imperfect systems. However, percent yields greater than 100% are possible, such as our question, if the measured product of the reaction contains impurities that cause its mass to be greater than it actually would be if the product was pure.

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use the heisenberg uncertainty principle to calculate the uncertainity in meters in the position of 0.68g and traveling at a vel
My name is Ann [436]

Answer:

7.7439×10⁻³¹ m

Explanation:

The expression for Heisenberg uncertainty principle is:

\Delta x\times \Delta v=\frac {h}{4\times \pi\times m}

Where m is the mass of the microscopic particle

h is the Planks constant

Δx is the uncertainty in the position

Δv is the uncertainty in the velocity

Given:

mass = 0.68 g = 0.68×10⁻³ kg

Δv = 0.1 m/s

Δx= ?

Applying the above formula as:

\Delta x\times 0.1=\frac {6.62\times 10^{-34}}{4\times \frac {22}{7}\times 0.68\times 10^{-3}}

<u>Δx = 7.7439×10⁻³¹ m</u>

8 0
4 years ago
What do you get if you do zinc and aluminum chloride
olchik [2.2K]
Zinc chloride and aluminum
5 0
3 years ago
What is the third period element with 2 valence electrons
tia_tia [17]

Answer:

<em>The</em><em> name of the element is magnesium </em>

I Hope this is right if not so sorry :)

7 0
3 years ago
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stellarik [79]

Answer: YES!

Explanation:

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3 0
3 years ago
A solution of NaOH is titrated with H2SO4. It is found that 20.05 mL of 0.3564 M H2SO4 solution is equivalent to 43.42 mL of NaO
Darya [45]

Answer : The concentration of NaOH is, 0.336 M

Explanation:

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=0.3564M\\V_1=20.05mL\\n_2=1\\M_2=?\\V_2=43.42mL

Putting values in above equation, we get:

2\times 0.3564M\times 20.05mL=1\times M_2\times 43.42mL

M_2=0.336M

Thus, the concentration of NaOH is, 0.336 M

3 0
3 years ago
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