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pashok25 [27]
3 years ago
15

A substance is tested with litmus paper. the blue litmus paper remains blue while the red limtus paper remains red. what can you

conclude about the substance
Chemistry
1 answer:
stich3 [128]3 years ago
4 0
It’s neutral with a pH of 7. It’s probably water.
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Which molecule has polar bonding and is nonpolar? A. H2O B. BF3 C. NH3 D. NCl3 E. CH2Cl2
Marina CMI [18]

Answer:

B. BF₃

Explanation:

All the molecules have polar bonds, but a molecule will be nonpolar if the molecule has the symmetry that makes the bond dipoles cancel.

To make the decision, we must

  1. Draw the Lewis structure
  2. Assign the VSEPR electron geometry
  3. Determine the molecular shape.
  4. Examine the symmetry of the molecule

===============

<em>A. Water </em>

Lewis structure = H-O-H (2 bonding pairs, 2 lone pairs)

Electron geometry = AX₂E₂ tetrahedral

Molecular geometry = bent

Symmetry (see Figure A): The two O-H bonds are polar, with their negative ends pointing towards the O. The horizontal components of the bond dipoles cancel, but the vertical components reinforce each other and give an upward pointing molecular dipole. This is a <em>polar molecule with polar bonds</em>.

===============

<em>B. Boron trifluoride </em>

Lewis structure = BF₃ (3 bonding pairs)

Electron geometry = AX₃, trigonal planar

Molecular geometry = trigonal planar

Symmetry (see Figure B): The three B-F bonds are polar, with their negative ends pointing towards the F. The horizontal components of the bond dipoles cancel, but the vertical components of the two downward -pointing dipoles reinforce each other and give a resultant that is equal and opposite to the upward dipole. Thus, the bond dipoles cancel. This is a nonpolar molecule with polar bonds.

===============

<em>C. Ammonia</em>

Lewis structure = :NH₃ (3 bonding pairs, 1 lone pairs)

Electron geometry = AX₃E, tetrahedral

Molecular geometry = trigonal pyramidal

Symmetry (see Figure C): The three N-H bonds are polar, with their negative ends pointing towards the N. The horizontal components of the bond dipoles cancel, but the vertical components reinforce each other and give an upward pointing molecular dipole. This is a <em>polar molecule with polar bonds</em>.

===============

<em>D. Nitrogen trichloride </em>

Lewis structure = :NCl₃ (3 bonding pairs, 1 lone pair)

Electron geometry = AX₃E, tetrahedral

Molecular geometry = trigonal pyramidal

Symmetry (see Figure D): The three N-Cl bonds are polar, with their negative ends pointing towards the Cl. The horizontal components of the bond dipoles cancel, but the vertical components reinforce each other and give a downward pointing molecular dipole. This is a <em>polar molecule with polar bonds</em>.

===============

<em>E. Dichloromethane </em>

Lewis structure = H₂CCl₂ (4 bonding pairs)

Electron geometry = AX₄, tetrahedral

Molecular geometry = tetrahedral

Symmetry (see Figure E): The two C-H bonds are nonpolar, but the two C-Cl bonds are polar with their negative ends pointing towards the Cl. The horizontal components of the bond dipoles cancel, but the vertical components reinforce each other and give a downward pointing molecular dipole. This is a <em>polar molecule with polar bonds</em>.

3 0
3 years ago
How does it feel like to drown
kykrilka [37]

Answer:

when you drown your lungs fill up with water so it like severe pain that won't go away until your dead so it like drink milk through nose imagine that and you can't breath that is what it is like to drown

Explanation:

3 0
3 years ago
Flowering plants are the most successful group of land plants. This is due, in part, to the trait that could be the label for po
jek_recluse [69]

Answer:

seeds are protected in fruits in such kind of plants.

Explanation:

The flowering plants are also known as Angiospermae, or Magnoliophyta. Flowering plants are plants that grow flowers. Such plants use seeds to reproduce, or make more plants like them.

Seeds are protected in fruits in such kinds of plants.

Examples of flowering plants are daisies, tulips, oaks, apples.

8 0
4 years ago
If a small amount of br2 is added to an aqueous solution of an unknown monosaccharide, the reddish-brown color of br2 will disap
Natalija [7]
Answer:
            <span>If a small amount of br2 is added to an aqueous solution of an unknown monosaccharide, the reddish-brown color of br2 will disappear if the monosaccharide is <u>an Aldose</u>.

Explanation:
                  This happens because the Aldose contains a carbonyl group called Alsedyde. Bromine being a oxidizing agent oxidizes the aldehyde functional group to Carboxylic Acid moiety. While this test is not positive in case of Ketonic Functional group.</span>

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3 years ago
Identify the environmental factor that caused the change in gene expression in the previous question. *
Arlecino [84]
It depends what Is the previous question
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3 years ago
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