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jeka94
3 years ago
10

Based on newtons first law of motion which of the following describes the action of an unbalanced force on a car

Physics
1 answer:
Pie3 years ago
4 0
It’s a car that is braking. Because any other object in or on the car would move on und the same direction the car did before it started to brake.
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Why does ice float in your drink but, your sunglasses sink in the pool?
kykrilka [37]

Answer:

cause Ice is lighter than sunglasses

4 0
3 years ago
1. Calculate the work done by a 47 N force pushing a pencil 0.26 m.<br> 47x .26 = 12J<br> Solve it
ziro4ka [17]

Answer:

I need help with one to

Explanation:

Im trying to ask someone but no one knows :(

7 0
3 years ago
A force is acting on a 3-kg object during 5 seconds. If the object initially has a speed of 1.5m/s and after applying the force
uranmaximum [27]

Answer:

1.5 N

Explanation:

You've left us to guess what the question is. I will Assume it is what's the force?

Givens

m = 3 kg

vi = 1.5 m/s

vf = 4 m/s

t = 5 seconds

Formula

F = m * (vf - vi)/t

Solution

F = 3 * (4 - 1.5) / 5

F = 1.5 N

3 0
3 years ago
A substance of unknown mass absorbs 138 kilojoules of energy, going from 298 to 303 kelvin. if the specific heat of the substanc
AveGali [126]

Heat absorbed to raise the temperature is given by

Q = mc\Delta T

here

m = mass

c = 7.11 J/g C

\Delta T = 303 - 298 = 5 kelvin

Q = 138 KJ

Now by using the above formula we will have

138 * 10^3 = m* 7.11 * 5

m = 3881 gram

m = 3.88 kg

So the amount of the substance will be 3.88 kg

4 0
4 years ago
1) A crane uses an average force of 5,200 N to lift a girder 25 m. How much work does the crane do on the girder?
Andrej [43]

Answer:

1) 130, 000 J

2) 1 J

Explanation:

1)

Work done is product of force in Newtons and distance in meters

W=Fd

Given an average force of 5,200 N and distance of 25 m then we evaluate that

Work done=5200*25=130, 000 Nm or Joules

2)

Similarly, for the second question, given force of 1N and distace of 1 m then the work done will be

W=1*1=1 J

8 0
3 years ago
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