Question

Urgent! Please help me solve this Chemistry problem.

Answer 1

Considering the equation,

3Na₂SO₄(aq)+2Al(NO₃)₃(aq)------>Al₂(SO₄)₃(s)+6NaNO₃(aq)

As it can be seen from the equation,

2 moles of Al(NO₃)₃ reacts with 3 moles of Na₂SO₄ to give 1 mol of Al₂(SO₄)₃.

Here 690 mL of 2.5 M Al(NO₃)₃=2.5× 690/1000

=1.7 mol of Al(NO₃)₃

As 2 moles of Al(NO₃)₃ give 1 mol of Al₂(SO₄)₃

So 1.7 mol of Al(NO₃)₃ give 1.7/2 mol of Al₂(SO₄)₃

so it will give 0.86 mol of Al₂(SO₄)₃.

Moles=mass given /molar mass

molar mass of Al₂(SO₄)₃= 342.1509 g/mol

Moles= mass given/342.1509

0.86=mass given/342.1509

mass of Al₂(SO₄)₃=295.1 g

so 295.1 g of Al₂(SO₄)₃ will be produced.