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Zielflug [23.3K]
4 years ago
7

What is the most abundant gas in the atmosphere is _____. argon oxygen nitrogen hydrogen

Chemistry
2 answers:
Serga [27]4 years ago
7 0
Hey there princesswalkeror4ori,

By far, the most abundant gas in the Earth's atmosphere<span> is </span>nitrogen<span>, which accounts for about 78% of the mass of dry air. </span>Oxygen is<span> the next most abundant gas, present at levels of 20 to 21%. Although humid air seems like it contains a lot of water, the maximum </span>amount of water vapor<span> that air can hold is only about 4%.
</span>
Hope I helped!

Have a great day!

pickupchik [31]4 years ago
5 0

------------------Nitrogen

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What type of energy is stored in the earths crust and produces earthquakes
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A rapid release of stored up energy 
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4. Why can't the subscripts be changed in a chemical equation in chemistry
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If you change the subscripts it would change the reactants or products and then you would be solving a different formula, you would change what the chemical is
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3 years ago
The following question appears on a quiz: ""You fill a tank with gas at 60°C to 100 kPa and seal it. You decrease the temperatu
dusya [7]

Answer: The final pressure will decrease ad the value is 85 kPa

Explanation:

To calculate the final pressure of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1\text{ and }T_1 are the initial pressure and temperature of the gas.

P_2\text{ and }T_2 are the final pressure and temperature of the gas.

We are given:

P_1=100kPa\\T_1=60^0C=(60+273)K=333K\\P_2=?\\T_2=10^0C=(10+273)K=283K

Putting values in above equation, we get:

\frac{100kPa}{333K}=\frac{P_2}{283K}\\\\P_2=85kPa

Hence, the final pressure will decrease ad the value is 85 kPa

8 0
3 years ago
A car with a mass of 1,100 kg is moving with a velocity of 30 m/s due east . What is the moment?
dexar [7]
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6 0
3 years ago
If a sample containing 18.1 g of NH3 is reacted with 90.4 g of
USPshnik [31]

Answer:

3.64g

Explanation:

Given parameters:

Mass of NH₃  = 18.1g

Mass of Cu₂O  = 90.4g

Unknown:

Limiting reactant  = ?

Mass of N₂ formed  = ?

Solution:

The reaction equation is given as:

       Cu₂O + 2NH₃ → 6Cu + N₂ + 3H₂O

The limiting reactant is the one in short supply in the reaction. Let us find the number of moles of the given species;

  Number of moles = \frac{mass}{molar mass}  

Molar mass of Cu₂O = 2(63.6) + 16  = 143.2g/mol

Molar mass of NH₃  = 14 + 3(1) = 17g/mol

Number of moles of Cu₂O = \frac{18.1}{143.2}   = 0.13moles

Number of moles of NH₃   = \frac{90.4}{17}   = 5.32moles

  From this reaction;

       1 mole of  Cu₂O combines with 2 mole of NH₃

So   0.13moles of  Cu₂O will combine with 0.13 x 2 mole of NH₃

                                              = 0.26moles of NH₃

Therefore, Cu₂O is the limiting reactant. Ammonia is in excess;

Mass of N₂;

   Mass = number of moles x molar mass

    1 mole of Cu₂O  will produce 1 mole of N₂

    0.13 mole of Cu₂O  will produce 0.13 mole of N₂

    Mass  = 0.13 x (2 x 14) = 3.64g

5 0
3 years ago
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