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evablogger [386]

3 years ago

7

I just need help guys

1 answer:

yarga [219]3 years ago

4 0

1 is 20

2 is 40

3 is 60

4 is 80

5 is 100

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Which number line shows the solution set for |y-9| <12

RUDIKE [14]

Answer:

Option c

$y\geq-3$ or $y \leq 21$

Step-by-step explanation:

The absolute value is a function that transforms any value x into a positive number.

Therefore, for the function $f(x) = |x|$ x> 0 for all real numbers.

Then the inequation:

$|y-9| \leq 12$ has two cases

$(y-9)$ if $y \geq 9$ (i)

$-(y-9)$ if $y < 9$ (ii)

We solve the case (i)

$y \leq 9 + 12\\y\leq21$

We solve the case (ii)

$-y +9 \leq 12\\-y \leq 12-9\\y \geq -3$

Then the solution is:

$y\geq-3$ or $y \leq 21$

8 0

2 years ago

Hirva ate 5/8 of a medium pizza. Elizabeth ate 1/4 of the pizza. How much pizza did they eat altogether?

Tcecarenko [31]

5/8 + 1/4 = (5+2)/8 = 7/8

7 0

3 years ago

Read 2 more answers

What is the slope of a line perpendicular to the line passing through (1, -3) and (-4, 7)?

andrezito [222]

Answer:

-2

Step-by-step explanation:

m= $\frac{y2-y1}{x2-x1}$

7 0

3 years ago

Solve 6 sin((π/5)x)=5 for the four smallest positive solutions

cupoosta [38]

Answer:

1.568, 3.432, 11.568, 13.432

Step-by-step explanation:

Divide equation $6\sin\left(\dfrac{\pi }{5}x\right)=5$ by 6:

$\sin\left(\dfrac{\pi }{5}x\right)=\dfrac{5}{6}.$

Then

$\dfrac{\pi }{5}x=(-1)^k\arcsin\left(\dfrac{5}{6}\right)+\pi k,\ k\in Z,$

$x=(-1)^k\dfrac{5}{\pi }\arcsin\left(\dfrac{5}{6}\right)+5k,\ k\in Z.$

Since $\arcsin\left(\dfrac{5}{6}\right)\approx 56^{\circ}\approx \dfrac{\pi }{3.2},$

four smallest positive solutions are

1. $\dfrac{5}{3.2}\approx 1.568,\ k=0;$

2. $\dfrac{-5}{3.2}+5\approx 3.432,\ k=1;$

3. $\dfrac{5}{3.2}+10\approx 11.568,\ k=2;$

4. $\dfrac{-5}{3.2}+15\approx 13.432,\ k=3.$

3 0

3 years ago

A hardware store rents vacuum cleaners that customers may use for part or all of a day, up to 12 hours, before returning. The st

jek_recluse [69]

The flat fee that the store charges is $14 and the cost for 7 hours is $56

A linear equation is on the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

let f for the total rental cost of a vacuum cleaner for x hours

Using the points (1, 20) and (3, 32) from the table:

$f-f_1=\frac{f_2-f_1}{x_2-x_1} (x-x_1)\\\\f-20=\frac{32-20}{3-1} (x-1)\\\\f(x)=6x+14$

The flat fee that the store charges is $14

The reasonable domain is 1 ≤ x ≤ 12

The cost for 7 hours is:

f(7) = 6(7) + 14 = 46

Find out more on linear equation at: brainly.com/question/14323743

4 0

2 years ago