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natulia [17]
3 years ago
6

When a beta particle is released from a nucleus of an atom:

Chemistry
1 answer:
tatiyna3 years ago
6 0
The correct answer is option B. i.e. the number of protons is increased.

In beta-particle emission, a neutron is changed into proton, electron and electron neutrino. The electron is emitted as beta particle and the proton remains inside the atom. Thus, the mass number remains same but the atomic number increases by one.
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How do we view large areas of earth’s surface?
ikadub [295]

Answer: Are there options? I think the answer is continents, but I don't really understand the question. Is continents an option?

Explanation:

6 0
3 years ago
The green light emitted by a stoplight has a wavelength of 505 nm. What is the frequency of this photon? (c = 3.00 × 10⁸ m/s).
Kitty [74]

Answer:

5.9405*10^14 Hz

Explanation:

Remember the equation c=v*λ

v=frequency

λ=wavelength

By manipulating the equation, we can get it in terms of frequency:

c/λ=v

Now convert wavelength to meters (1nm=m*10^-9)

5.05*10^-7m (2 decimal places were shifted to make the number between 1-10, hence the -7 exponent)

Use the manipulated equation:

(3.00*10^8)/(5.05*10^-7), which yields:

5.9405*10^14 Hz (or s^-1)

6 0
3 years ago
PLEASE HELP!! LAST QUESTION IM RUNNING OUT OF TIME!!
Brums [2.3K]
The answerrrrrrr i (B)
7 0
4 years ago
The henry's law constant for helium gas in water at 30C is3.70x10-4 M/atm. when the partial pressure ofhelium above a sample of
SIZIF [17.4K]

Answer:

a. S = 2.41 x 10⁻⁴ M

Explanation:

The solubility S of a gas in water at a given temperature  is given by the equation

S = Kp where S= solubility of the gas

                       K= Henry's Constant for the gas

                       p = partial pressure of the gas

solving for S

S = 3.70 x 10⁻⁴ M/atm x 0.650 atm =2.41 x 10⁻⁴ M

5 0
3 years ago
A gas has a volume of 240.0mL at 25.0 oC and 0.79 atm. Calculate its volume at STP (1 atm and 0 oC).
baherus [9]

Answer:

189.6 mL

Explanation:

As per Boyles law when a gas is kept at a constant temperature and mass in a closed container, the volume and pressure vary inversely.

P1V1= P2V2

Here, P1 = 0.79 atm, V1 = 240 ml, P2= 1 atm

therefore, substituting values in above equation we get

0.79×240 = 1×V2

⇒V2 = 189.6 ml

therefore,  its volume at STP (1 atm and 0 oC) = 189.6 ml

3 0
3 years ago
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