the answer is C. the solute polar water itself is a polar solvent so it combines well with other polar solvents (which basically have polar molecules)
Answer:
![\large \boxed{\text{44.5 mL}}](https://tex.z-dn.net/?f=%5Clarge%20%5Cboxed%7B%5Ctext%7B44.5%20mL%7D%7D)
Explanation:
When adding or subtracting values, you must round your answer to the same "place" as the measurement with its last significant figure furthest to the left.
That is, you round off to the same number of decimal places as the measurement with the fewest decimal places.
![\begin{array}{r|r}19.9& \text{3 mL}\\14.0&\text{mL}\\10.6&\text{mL} \\\mathbf{44.5} &\textbf{3 mL}\\\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Br%7Cr%7D19.9%26%20%5Ctext%7B3%20mL%7D%5C%5C14.0%26%5Ctext%7BmL%7D%5C%5C10.6%26%5Ctext%7BmL%7D%20%5C%5C%5Cmathbf%7B44.5%7D%20%26%5Ctextbf%7B3%20mL%7D%5C%5C%5Cend%7Barray%7D)
The measurements of 14.0 and 10.6 have one digit after the decimal point, so you round the sum to have only one digit to the right of the decimal.
The number to be dropped (3) is less than 5, so you drop it.
![\text{The total volume of the three beakers is $\large \boxed{\textbf{44.5 mL}}$}](https://tex.z-dn.net/?f=%5Ctext%7BThe%20total%20volume%20of%20the%20three%20beakers%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B44.5%20mL%7D%7D%24%7D)
Answer:
Answer is given below.
Explanation:
Anode is that electrode where oxidation occurs. Cathode is that electrode where reduction occurs.
In cell representation, half cell present left to salt-bridge notation
is anodic system and another half cell present right to salt-bridge notation
is cathodic system.
So anode is Cu and cathode is Ag.
oxidation: ![Cu-2e^{-}\rightarrow Cu^{2+}(aq.)](https://tex.z-dn.net/?f=Cu-2e%5E%7B-%7D%5Crightarrow%20Cu%5E%7B2%2B%7D%28aq.%29)
[reduction:
]![\times 2](https://tex.z-dn.net/?f=%5Ctimes%202)
-----------------------------------------------------------------------------------------------
chemical equation: ![Cu+2Ag^{+}(aq.)\rightarrow Cu^{2+}(aq.)+2Ag](https://tex.z-dn.net/?f=Cu%2B2Ag%5E%7B%2B%7D%28aq.%29%5Crightarrow%20Cu%5E%7B2%2B%7D%28aq.%29%2B2Ag)
Oxidizing agent is that species which takes electron from another species. Here
takes electron from Cu. Hence
is the oxidizing agent.
Reducing agent is that species which gives electron to another species. Here Cu gives electron to
. Hence Cu is the reducing agent.
Antimony Tribromide is the answer