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atroni [7]
3 years ago
11

A spinning ice skater will slow down if she extends her arms away from her body. Which of the following statements explains this

phenomenon?
Physics
1 answer:
klasskru [66]3 years ago
6 0
Drag from her armas would slow her down if she was spinning at a fast speed
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What is the velocity (m/s) after 5 seconds of fall
gregori [183]
5 second fall starting at 0 m/s
ball strikes ground at a speed = 49 meters per second.
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3 years ago
A state patrol officer saw a car start from rest at a highway​ on-ramp. She radioed ahead to another officer 20 mi along the hig
Vikentia [17]

Answer:

We know from the basic speed distance relation that

Speed=\frac{Distance}{Time}

Since the car started from rest and it covered the distance between the 2 officer's in 19 minutes we have speed of the car

Speed=\frac{Distance}{Time}\\\\Speed=\frac{20}{\frac{19}{60}}=63.16mph

Which clearly exceeds the limit of 60\frac{mi}{hr}

5 0
3 years ago
A boy throws a ball up into the air with a speed of 8.2 m/s. The ball has a mass of 0.3 kg. How much gravitational potential ene
diamong [38]
We can use the law of conservation of energy to solve the problem.

The total mechanical energy of the system at any moment of the motion is:
E=U+K = mgh + \frac{1}{2}mv^2
where U is the potential energy and K the kinetic energy.

At the beginning of the motion, the ball starts from the ground so its altitude is h=0 and therefore its potential energy U is zero. So, the mechanical energy is just kinetic energy:
E_i = K_i =  \frac{1}{2}mv^2 =  \frac{1}{2}(0.3 kg)(8.2 m/s)^2=10.09 J

When the ball reaches the maximum altitude of its flight, it starts to go down again, so its speed at that moment is zero: v=0. So, its kinetic energy at the top is zero. So the total mechanical energy is just potential energy:
E_f = U_f
But the mechanical energy must be conserved, Ef=Ei, so we have
U_f = K_i
and so, the potential energy at the top of the flight is
U_f = K_i = 10.09 J
7 0
3 years ago
Read 2 more answers
A plane travels at a speed of 205mph in still air. Flying with a tailwind, the plane is clocked over a distance of 1000 miles. F
vaieri [72.5K]

While plane is moving under tailwind condition it took time "t"

so here we will have

t = \frac{d}{v_{net}}

here net speed of the plane will be given as

v_{net} = v + v_w

t = \frac{1000}{205 + v_w}

similarly when it moves under the condition of headwind its net speed is given as

v_{net} = v - v_w

now time taken to cover the distance is 2 hours more

t + 2 = \frac{1000}{205 - v_w}

now solving two equations

\frac{1000}{205 + v_w} + 2 = \frac{1000}{205 - v_w}

solving above for v_w we got

v_w = 40.4 mph

6 0
3 years ago
How does the scientific process generally begin?
Murljashka [212]
There are several approaches. The most favourable one (in my opinion) is this one:
1. Asking a question
2. Doing a research (how to answer this question)
3. Creating a hypothesis (NOT a thesis!)
4. Experimenting (to prove the hypothesis)
5. Analysing results from the experiment
6. Writing a thesis
5 0
3 years ago
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