Answer:
When the ball is held motionless above the floor, the ball possesses only GPE energy.If the ball is dropped, its GPE energy decreases as it falls.If the ball is dropped, its KE energy increases as it falls.
Explanation:
If the ball is held motionless, then its kinetic energy is equal to zero, since kinetic energy depends on the velocity. And the ball is held above the ground, which means it possesses gravitational potential energy.
If the ball is dropped, its height will decrease, therefore its gravitational potential energy will decrease. Along the way, the ball will be in free fall, and therefore its velocity will increase, hence its kinetic energy.
![K = \frac{1}{2}mv^2\\U = mgh](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B1%7D%7B2%7Dmv%5E2%5C%5CU%20%3D%20mgh)
Answer:
1.25 kgm²/sec
Explanation:
Disk inertia, Jd =
Jd = 1/2 * 3.7 * 0.40² = 0.2960 kgm²
Disk angular speed =
ωd = 0.1047 * 30 = 3.1416 rad/sec
Hollow cylinder inertia =
Jc = 3.7 * 0.40² = 0.592 kgm²
Initial Kinetic Energy of the disk
Ekd = 1/2 * Jd * ωd²
Ekd = 0.148 * 9.87
Ekd = 1.4607 joule
Ekd = (Jc + 1/2*Jd) * ω²
Final angular speed =
ω² = Ekd/(Jc+1/2*Jd)
ω² = 1.4607/(0.592+0.148)
ω² = 1.4607/0.74
ω² = 1.974
ω = √1.974
ω = 1.405 rad/sec
Final angular momentum =
L = (Jd+Jc) * ω
L = 0.888 * 1.405
L = 1.25 kgm²/sec
Answer:
<em>Velocity is the rate at which the position changes</em>
<em>Velocity is the rate at which the position changesWhy do we need</em>
<em>Velocity is the rate at which the position changesWhy do we needVectors make it convenient to handle quantities going in different directions</em><em>.</em><em>.</em><em> </em>
Explanation:
Thank you!
The speed of a electron that is accelerated from rest through an electric potential difference of 120 V is ![6.49\times10^6m/s](https://tex.z-dn.net/?f=6.49%5Ctimes10%5E6m%2Fs)
<h3>
How to calculate the speed of the electron?</h3>
We know, that the energy of the system is always conserved.
Using the Law of Conservation of energy,
U=0
Here, K is the kinetic energy and U is the potential energy.
Now, substituting the formula of U and K, we get:
=0------(1)
Here,
m is the mass of the electron
v is the speed of the electron
q is the charge on the electron
V is the potential difference
Let
and
represent the final and initial speed.
Here,
=0
Solving for
, we get:
![v_f=\sqrt{\frac{-2q\triangle V}{m} }](https://tex.z-dn.net/?f=v_f%3D%5Csqrt%7B%5Cfrac%7B-2q%5Ctriangle%20V%7D%7Bm%7D%20%7D)
![=\sqrt{\frac{2\times1.602\times10^{-19}\times 120}{9.109\times10^{-31}} }](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%5Cfrac%7B2%5Ctimes1.602%5Ctimes10%5E%7B-19%7D%5Ctimes%20120%7D%7B9.109%5Ctimes10%5E%7B-31%7D%7D%20%7D)
=6.49
m/s
To learn more about the conservation of energy, refer to:
brainly.com/question/2137260
#SPJ4