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3 years ago

11

Write a function call with arguments tensPlace, onesPlace, and userInt. Be sure to pass the first two arguments as pointers. Sam

ple output for the given program: tensPlace = 4, onesPlace = 1

1 answer:

Trava [24]3 years ago

4 0

Answer:

#include <stdio.h>

void SplitIntoTensOnes(int* tensDigit, int* onesDigit, int DecVal){

*tensDigit = (DecVal / 10) % 10;

*onesDigit = DecVal % 10;

return;

}

int main(void) {

int tensPlace = 0;

int onesPlace = 0;

int userInt = 0;

userInt = 41;

SplitIntoTensOnes(&tensPlace, &onesPlace, userInt);

printf("tensPlace = %d, onesPlace = %d\n", tensPlace, onesPlace);

return 0;

}

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(35-39) A student travels on a school bus in the middle of winter from home to school. The school bus temperature is 68.0° F. Th

arlik [135]

Answer:

The net energy transfer from the student's body during the 20-min ride to school is 139.164 BTU.

Explanation:

From Heat Transfer we determine that heat transfer rate due to electromagnetic radiation ( $\dot Q$ ), measured in BTU per hour, is represented by this formula:

$\dot Q = \epsilon\cdot A\cdot \sigma \cdot (T_{s}^{4}-T_{b}^{4})$ (1)

Where:

$\epsilon$ - Emissivity, dimensionless.

$A$ - Surface area of the student, measured in square feet.

$\sigma$ - Stefan-Boltzmann constant, measured in BTU per hour-square feet-quartic Rankine.

$T_{s}$ - Temperature of the student, measured in Rankine.

$T_{b}$ - Temperature of the bus, measured in Rankine.

If we know that $\epsilon = 0.90$ , $A = 16.188\,ft^{2}$ , $\sigma = 1.714\times 10^{-9}\,\frac{BTU}{h\cdot ft^{2}\cdot R^{4}}$ , $T_{s} = 554.07\,R$ and $T_{b} = 527.67\,R$ , then the heat transfer rate due to electromagnetic radiation is:

$\dot Q = (0.90)\cdot (16.188\,ft^{2})\cdot \left(1.714\times 10^{-9}\,\frac{BTU}{h\cdot ft^{2}\cdot R^{4}} \right)\cdot [(554.07\,R)^{4}-(527.67\,R)^{4}]$

$\dot Q = 417.492\,\frac{BTU}{h}$

Under the consideration of steady heat transfer we find that the net energy transfer from the student's body during the 20 min-ride to school is:

$Q = \dot Q \cdot \Delta t$ (2)

Where $\Delta t$ is the heat transfer time, measured in hours.

If we know that $\dot Q = 417.492\,\frac{BTU}{h}$ and $\Delta t = \frac{1}{3}\,h$ , then the net energy transfer is:

$Q = \left(417.492\,\frac{BTU}{h} \right)\cdot \left(\frac{1}{3}\,h \right)$

$Q = 139.164\,BTU$

The net energy transfer from the student's body during the 20-min ride to school is 139.164 BTU.

7 0

3 years ago

Suppose the working pressure for a boiler is 10 psig, then what is the corresponding absolute pressure?

yanalaym [24]

Answer:

The corresponding absolute pressure of the boiler is 24.696 pounds per square inch.

Explanation:

From Fluid Mechanics, we remember that absolute pressure ( $p_{abs}$ ), measured in pounds per square inch, is the sum of the atmospheric pressure and the working pressure (gauge pressure). That is:

$p_{abs} = p_{atm}+p_{g}$ (1)

Where:

$p_{atm}$ - Atmospheric pressure, measured in pounds per square inch.

$p_{g}$ - Working pressured of the boiler (gauge pressure), measured in pounds per square inch.

If we suppose that $p_{atm} = 14.696\,psi$ and $p_{g} = 10\,psi$ , then the absolute pressure is:

$p_{abs} = 14.696\,psi+10\,psi$

$p_{abs} = 24.696\,psi$

The corresponding absolute pressure of the boiler is 24.696 pounds per square inch.

8 0

3 years ago

Ethylene glycol, the ingredient in antifreeze, does not cause health problems because it is a clear liquid.

netineya [11]

B. false

Explanation: because it is

5 0

3 years ago

A 800-MW steam power plant, which is cooled by a nearby river, has a thermal efficiency of 40 percent. Determine the rate of hea

Arturiano [62]

Answer:

Rate of heat transfer to river=1200MW

So the actual amount of heat rejected ti the river will be less as there will some heat loss to surrounding and in pipes

Explanation:

In order to find the actual heat transfer rate is lower or higher than its value we will first find the rate of heat transfer to power plant:

$Efficiency=\frac{work}{heat transfer to power plant}$

$Heat transfer=\frac{work}{Efficiency\\} \\\\Heat transfer=\frac{800}{0.40}\\\\Heat transfer=2000MW$

From First law of thermodynamics:

Rate of heat transfer to river=heat transfer to power plant-work done

Rate of heat transfer to river=2000-800

Rate of heat transfer to river=1200MW

So the actual amount of heat rejected ti the river will be less as there will some heat loss to surrounding and in pipes.

4 0

4 years ago

C#: Arrays - Ask the user how many students names they want to store. You will create two parallel arrays (e.g. 2 arrays with th

zhenek [66]

Answer:

using System;
public class Program
{
public static void Main()
{
Console.WriteLine("Enter number of students: ");
int num = Convert.ToInt32(Console.ReadLine());
string [] firstName = new string[num];
string [] lastName = new string[num];
for(int i=0 ; i < num; i++){
Console.WriteLine("Enter first name: ");
firstName[i] = Console.ReadLine();
Console.WriteLine("Enter last name: ");
lastName[i] = Console.ReadLine();
}
for(int j=0; j < num; j++){
Console.WriteLine(lastName[j] + "," + firstName[j]);
}
}
}

Explanation:

Firstly, prompt user to enter number of student to be stored (Line 6- 7). Next, create two array, firstName and lastName with num size (Line 8-9).

Create a for-loop to repeat for num times and prompt user to enter first name and last name and then store them in the firstName and lastName array, respectively (Line 11 - 17).

Create another for loop to traverse through the lastName and firstName array and display the last name and first name by following the format given in the question (Line 19 - 21).

4 0

3 years ago