Answer:
it is not possible to place the wires in the condui
Explanation:
given data
total area = 2.04 square inches
wires total area = 0.93 square inches
maximum fill conduit = 40%
to find out
Can it is possible place wire in conduit conduit
solution
we know maximum fill is 40%
so here first we get total area of conduit that will be
total area of conduit = 40% × 2.04
total area of conduit = 0.816 square inches
but this area is less than required area of wire that is 0.93 square inches
so we can say it is not possible to place the wires in the conduit
Answer:
Check the attached image below
Explanation:
Kindly check the attached image below to get the step by step explanation to the question above.
Answer:
The geometry is treated as a two surface enclosure because the two surfaces have the same properties.
Let's take the base surface to be surface 1, while the side surfaces are surface 2.
Let's take the heat transfer expression:
Where,
= base temperature
= surface 2 temperature = 500K
= emissivity of surface 1 = 0.8
= emissivity of surface 2 = 0.5
= Area
= shape factor
Substituting figures in the equation, we have:
The base temperature is 523.038 k
Answer:
Explanation:
1) First step would be determining the measured force through your experiment for the Reaction force of the both the surfaces on the jet of fluid stream. The value would be R_actual.
2) Second step is to compute the Reaction force by the theoretical model which takes an assumption of no kinetic energy loss from a jet of fluid stream impinging on to the surfaces i.e the velocity before and after impact is the same. This value would be R_theoratical.
3) Step Three would be to compare the actual and theoretical values of Reaction forces exerted by the surfaces by the following formula:
% Difference = [ ( R_actual - R_theoratical ) / R_actual ] * 100
4) The standard followed is that a theoretical model must predicts within 10% uncertainty about the actual value obtained from experiment.
5) If the difference is greater than 10% it means that the assumption of no Kinetic Energy Losses was not feasible and should be included in the model for accuracy.