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Archy [21]
4 years ago
8

Ari uses a tool called calipers to measure the diameter of different cylinders he is using in an experiment. His old calipers co

uld measure down to 0.01 mm, but his new calipers only measure down to 0.1 mm. Are his new calipers less precise, less accurate, both less accurate and less precise, or neither less precise or less accurate?
Physics
1 answer:
Vladimir [108]4 years ago
7 0

Answer:

Explanation:

Different measuring instruments have different level of precision . For example , our usual scale can measure upto 1 mm. Callipers can measure upto .1 mm. screw gauge can measure upto .01 mm.etc The deeper it can measure , the more precise it is. Hence screw gauge is most precise among the three.

On this basis we can say that , new caliper is less precise than old one.

Accuracy tells us about our result , how close our result is to the true measurement. It is dependent on  the manner in which  we take reading , So measuring methods , rather than measuring instruments , decide the accuracy of our result.

Hence we can say that the new caliper is less precise only.

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ad for the distance from the sun tothe earth is 1.5 x 10"m. how long does it take for light from ths sun to reach the eath? give
Alexandra [31]

Answer:

About 8.3 minutes

Explanation:

Use the formula for velocity as the distance covered by the light divided the time it takes: [tex]velocity=\frac{distance}{time}[/tex]

Use the information about the speed of light in vacuum: 300000000 \frac{m}{s} = 3*10^{8} \frac{m}{s}

and the information you are given regarding the distance between Sun and Earth: 1.5 * 10^{11} m

to solve the first velocity equation for the unknown time "t":

velocity=\frac{distance}{time} \\3*10^8\frac{m}{s} =\frac{1.5*10^11 m}{t} \\t=\frac{1.5*10^11 }{3*10^8} s= 500 s

we can convert second into minutes by dividing by 60: 500 s = 500/60 minutes = 8.3333... minutes

5 0
3 years ago
What is the escape speed for an electron initially at rest on the surface of a sphere with a radius of 1.3 cm and a uniformly di
Vlad [161]

Answer:

2.37 * 10^4 m/s

Explanation:

Constants :

Mass of electron = 9.11 * 10^(-31) kg

Electric charge of an electron = 1.602 * 10^(-19) C

Parameters given:

Radius of sphere = 1.3cm = 0.013m

Charge of sphere = 2.3 * 10^(−15) C

Using the law of conservation of energy, we have that:

K. E.(initial) + P. E.(initial) = K. E.(final) + P. E.(final)

K. E.(final) = 0, since final velocity is zero and P. E.(final) = 0 since the electron reaches a final distance of infinity.

Hence,

K. E.(initial) = P. E.(initial)

0.5mv^2 = (kqQ)/r

Where k = Coulumbs constant

Q = charge of the sphere.

r = radius of the sphere.

=> 0.5*m*v^2 = (kqQ)/r

0.5 * 9.11 * 10^(-31) * v^2 = (9 * 10^9 * 1.602 * 10^(-19) * 2.3 * 10^(-15))/0.013

4.555 * 10^(-31) * v^2 = 2550.88 * 10^(-25)

=> v^2 = 2550.88 * 10^(-25) / 4.555 * 10^(-31)

v^2 = 560 * 10^6 = 5.60 * 10^8

=> v = 2.37 * 10^4 m/s

4 0
3 years ago
A Ping-Pong ball has a mass of 2.3 g and a terminal speed of 9.2 m/s. The drag force is of the form bv2 What is the value of b?
Bingel [31]
Drag force is a force that resist the motion of a certain body through a fluid like air or water. This can be calculated through the equation,
                                    D = 0.5Cρv²
where D is drag, C is the drag coefficient, ρ is the density and v is the velocity. The value therefore of b in the item above is,
                                        b = 0.5Cρ
8 0
3 years ago
The acceleration due to gravity on planet a is one-sixth what it is on planet b, and the radius of the planet a is one-fourth th
nevsk [136]
The acceleration due to gravity on a large body is given by:
acceleration = (gravitational constant * mass of body) / radius²

For b, this is:
g = GM/r²
M = gr²/G

For a,
g(a) = 1/6 g
r(a) = 1/4 r
M(a) = g(a)r(a)²/G
M(a) = 1/6 g * (1/4 r)²/G
M(a) = gr²/96G

The fraction is given as:
M(a) / M = (gr²/96G) / (gr²/G)
M(a) / M = 1/96

The mass of planet a is 1/96 of the mass of planet b.
8 0
3 years ago
How does red shift of light emitted by distant stars and galaxies provide
o-na [289]

Answer:

It shows that stars are red.

Explanation:

Red is my favorite color!

8 0
3 years ago
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