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solong [7]
3 years ago
15

Circle.center:(2,-5).radius:9

Mathematics
1 answer:
Kaylis [27]3 years ago
8 0

Answer:

Step-by-step explanation:

eq. of circle with center (h,k) and radius=r is

(x-h)²+(y-k)²=r²

reqd. eq. is

(x-2)²+(y+5)²=9²

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Find the product.<br><br> (8-3z)(8+3z)
maks197457 [2]

Step-by-step explanation:

you can open the file I gave you now. the answer is there

7 0
2 years ago
300 ml of pure alcohol is poured from a bottle containing 2 l of pure alcohol. Then, 300 ml of water is added into the bottle. A
Ede4ka [16]

Answer:

The present percentage of pure alcohol in the solution is 72.25% of pure alcohol

Step-by-step explanation:

The volume of pure alcohol poured from the 2 l bottle of pure alcohol = 300 ml of pure alcohol

The volume of water added into the bottle after pouring out the pure alcohol = 300 ml of water

The volume of diluted alcohol poured out of the bottle = 300 ml of diluted alcohol

The volume of water added into the bottle of diluted alcohol after pouring out the 300 ml of diluted alcohol = 300 ml of water

Step 1

After pouring the 300 ml of pure alcohol and adding 300 ml of water to the bottle, the percentage concentration, C%₁ is given as follows;

C%₁ = (Volume of pure alcohol)/(Total volume of the solution) × 100

The volume of pure alcohol in the bottle = 2 l - 300 ml = 1,700 ml

The total volume of the solution = The volume of pure alcohol in the bottle +  The volume of water added = 1,700 ml + 300 ml = 2,000 ml = 2 l

∴ C%₁ = (1,700 ml)/(2,000 ml) × 100 = 85% percent alcohol

Step 2

After pouring out 300 ml diluted alcohol from the 2,000 ml, 85% alcohol and adding 300 ml of water, we have;

Volume of 85% alcohol = 2,000 ml - 300 ml = 1,700 ml

The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol = 85/100 × 1,700 = 1,445 ml

The total volume of the diluted solution = The volume of the 85% alcohol in the solution + The volume of water added

∴ The total volume of the twice diluted solution = 1,700 ml + 300 ml = 2,000 ml

The present percentage of pure alcohol in the solution, C%₂ = (The volume of pure alcohol in the 1,700 ml, 85% diluted alcohol)/(The total volume of the diluted solution) × 100

∴ C%₂ = (1,445 ml)/(2,000 ml) × 100 = 72.25 %

The present percentage of pure alcohol in the solution, C%₂ = 72.25%

3 0
3 years ago
I need help simplifying this problem:
Aliun [14]
C(t)= -0.3t^2 + 7.2t - 3.2

12c = 40
6 0
3 years ago
Answers for the 2 boxes please :)​
Lapatulllka [165]

Answer:

-2,3

Step-by-step explanation:

x = -2

y = 3

..........

8 0
3 years ago
​Simplify. ​13(−32.48−14.02)​ Enter your answer, as a decimal to tenths, in the box.
Artyom0805 [142]

If you mean 1/3 the answer is -15.5

1/3(-32.48-14.02) = 1/3(-46.5) = (-15.5)

3 0
3 years ago
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