<h2>Answer:</h2>
<u>Distance covered is 6.9 meters</u>
<h2>Explanation:</h2>
Data given:
Work Done = 345 kJ = 345000 J
Force = 5 x 10 ^ 4 = 50000 N
Distance = ?
Solution:
As we know that
Work Done = Force applied x Distance covered
By arranging the equation we get
Work / Force = Distance covered
By putting the values
345000 / 50000 = 6.9
So distance covered is 6.9 meters
Answer:
Explanation:
mass of the ball = 146 g = 146 / 1000 = 0.146 kg
initial speed of the ball = 40.6 m/s
final speed of the ball = - 45.1 m/s
time of impact = 1.05 ms = 1.05 / 1000 = 0.00105 s
impulse, Ft = change in momentum = mv - mu = m (v-u)
F = m (v - u) / t = 0.146 kg ( -45.1 -40.6) / 0.00105 s = -11916.4 N
Answer:
a lens that causes parallel light rays to separate from each other
Explanation:
1) For a positive point charge, the lines radiate outwards
for a negative point charge, the lines converge inwards
2) F = 2.3 X 10^-26 N
k = 9 X 10^9 N.m²/C
q1 = q2 = e = 1.6 X 10^-19 C
r = ?
F = kq1q2/r²
r² = kq1q2/F
r = √[kq1q2/F ]
r = √0.0100
r = 0.10m
The two protons are 0.10 m apart
3) The unit if electric field intensity is Newton-per-coulomb N/C
Answer:
B
Explanation:
Remark
If, when it reaches its maximum height where the PE is the greatest, that the maximum energy is when the ball is first kicked. That would mean its starting energy is 10 Joules.
Formula
KE = 1/2 m v^2
Givens
KE = 10 J
m = 0.2 kg
v = ?
Solution
10 = 1/2 * 0.2 * v^2
10 * 2 = 0.2 * v^2
20 = 0.2 * v^2
20/0.2 = v^2
100 = v^2
v = 10 m/s
