If an object is dropped from a height of meters, the velocity (in ) at impact is given by v= √2gh , where g=9.8m/sec^2 is the ac
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Answer:
New Momentum of Ball B
<u>Explanation:</u>
Given:
Mass of Ball A=1kg
Mass of Ball B= 2kg
Mass of Ball C=5kg
Mass of Ball D=7kg
Velocities of A=B=C=D=2.2
Momentum of Ball A=2.2
Momentum of Ball B=4.4
Momentum of Ball C=11
Momentum of Ball D=15
To Find:
Change in Momentum When of Ball B gets tripled
Solution:
Though all balls have same velocity, thus we get
Velocities of A=B=C=D=2.2
Initial Momentum of Ball B=4.4
If the Mass of Ball B gets tripled;
We get New Mass of Ball B=3×Actual Mass of the ball
=3×2=6kg
Thus we get Mass of Ball B=6kg
According to the formula,
Change in momentum of Ball B
Where =change in momentum
m=mass of the ball B
=change in velocity ball B
And since all balls, have same velocity
Thus the above equation, changes to
Substitute all the values in the above equation we get
Result:
Thus the New Momentum of ball B
Answer:
1.24611
Explanation:
V = Velocity = 10 ft/s
L = Length = 2 ft
g = Acceleration due to gravity = 32.2 ft/s²
Froude number is given by
Converting to SI units
The Froude number is 1.24611
The Froude number is equal. The Froude number is dimensionless as the units cancel each other. In order for this to happen the units used need to be consitent either imperial or SI.