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stellarik [79]
3 years ago
11

6. Rebecca is playing softball and slides into home plate. Her weight is 600N. The Coefficient of static friction between her cl

othes and the ground is 0.62
Physics
2 answers:
scoray [572]3 years ago
6 0

372 Newton is the answwr

son4ous [18]3 years ago
5 0

Answer:

if you are asking for static friction the answer is  <u>372N</u>

Explanation

friction static=normal force x coefficient of static friction

and normal force is equal to weight of a body

so  static friction = 600N x 0.62= 372N

You might be interested in
A 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s west. Find the ve
Troyanec [42]

The velocity of tennis racket after collision is 14.96m/s

<u>Explanation:</u>

Given-

Mass, m = 0.311kg

u1 = 30.3m/s

m2 = 0.057kg

u2 = 19.2m/s

Since m2 is moving in opposite direction, u2 = -19.2m/s

Velocity of m1 after collision  = ?

Let the velocity of m1 after collision be v

After collision the momentum is conserved.

Therefore,

m1u1 - m2u2 = m1v1 + m2v2

v1 = (\frac{m1-m2}{m1+m2})u1 + (\frac{2m2}{m1+m2})u2

v1 = (\frac{0.311-0.057}{0.311+0.057})30.3 + (\frac{2 X 0.057}{0.311 + 0.057}) X-19.2\\\\v1 = (\frac{0.254}{0.368} )30.3 + (\frac{0.114}{0.368}) X -19.2\\ \\v1 = 20.91 - 5.95\\\\v1 = 14.96

Therefore, the velocity of tennis racket after collision is 14.96m/s

7 0
3 years ago
Rock formed from harden magma that rises to the surface is called ​
salantis [7]

Answer:

Igneous rocks

Explanation:

3 0
3 years ago
A 400-kg object has a 100-Newton rightward net force being applied to it. What is the magnitude of the rightward acceleration on
aliya0001 [1]

Answer:

The answer to your question is a = 0.25 m/s²

Explanation:

Data

mass = m = 400 kg

Force = F = 100 N

acceleration = a = ? m/s²

Process

To solve this problem use Newton's second law that states that the force applied to an object is directly proportional to the mass of the body times its acceleration.

Formula

                       F = ma

solve for a

                       a = \frac{F}{m}

Substitution

                       a = \frac{100}{400}

Simplification and result

                              a = 0.25 m/s²

5 0
3 years ago
ball is dropped from rest and hits the ground 1.1 seconds later. What height was the ball released from? ​
Aleonysh [2.5K]
Height = 1/2 * 9.8 * (1.1^2)
5 0
3 years ago
Una patinadora de 50 kg parte del reposo y después de recorrer 3k alcanza una velocidad de 15 m/s. ¿Qué fuerza neta experimenta
e-lub [12.9K]

Answer:

F_{net} = 1.875\,N

Explanation:

Asúmase que la patinadora experimenta una aceleración constante. La fuerza neta experimentada por la patinadora:

F_{net} = (50\,kg)\cdot \left[\frac{\left(15\,\frac{m}{s}\right)^{2}-\left(0\,\frac{m}{s}\right)^{2} }{2\cdot (3000\,m)} \right]

F_{net} = 1.875\,N

6 0
3 years ago
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