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stellarik [79]
3 years ago
11

6. Rebecca is playing softball and slides into home plate. Her weight is 600N. The Coefficient of static friction between her cl

othes and the ground is 0.62
Physics
2 answers:
scoray [572]3 years ago
6 0

372 Newton is the answwr

son4ous [18]3 years ago
5 0

Answer:

if you are asking for static friction the answer is  <u>372N</u>

Explanation

friction static=normal force x coefficient of static friction

and normal force is equal to weight of a body

so  static friction = 600N x 0.62= 372N

You might be interested in
A cube that has a volume of 1.00 m³ contains N distinguishable particles.
grandymaker [24]

Answer:

1 P = 0.5

2 P = 0.3

3 P = 0.01

Explanation:

The probability formula is

          P =V^N

Where P is the probability  V is the volume while N is the number of distinguishing particles

So for N = 1 and V = 0.500m^3

           P = (0.500m^3)^1\\

               = 0.5

For  N = 1 and V =  0.300m^3

           P = (0.300m^3)^1

               = 0.3

For   N = 1 and V = 0.0100m^3

     P =(0.0100m^3)^1

         = 0.01

         

6 0
2 years ago
f a single circular loop of wire carries a current of 45 A and produces a magnetic field at its center with a magnitude of 1.50
Lelu [443]

Answer:

Radius of the loop is 0.18 m or 18 cm

Explanation:

Given :

Current flowing through the wire, I = 45 A

Magnetic field at the center of the wire, B = 1.50 x 10⁻⁴ T

Number of turns in circular wire, N = 1

Consider R be the radius of the circular wire.

The magnetic field at the center of the current carrying circular wire is determine by the relation:

B=\frac{N\mu_{0} I}{2R}

Here μ₀ is vacuum permeability constant and its value is 4π x 10⁻⁷ Tm/A.

Substitute the suitable values in the above equation.

1.50\times10^{-4} =\frac{4\pi \times10^{-7}\times45 }{2R}

R = 0.18 m

4 0
2 years ago
Desde una altura de 120 m se deja caer un cuerpo. Calcular a los 2,5 s i) la rapidez que lleva; ii) cuánto ha descendido; iii) c
stira [4]

Answer:

i) 24.5 m/s

ii) 30,656 m

iii) 89,344 m

Explanation:

Desde una altura de 120 m se deja caer un cuerpo. Calcule a 2.5 s i) la velocidad que toma; ii) cuánto ha disminuido; iii) cuánto queda por hacer

i) Los parámetros dados son;

Altura inicial, s = 120 m

El tiempo en caída libre = 2.5 s

De la ecuación de caída libre, tenemos;

v = u + gt

Dónde:

u = Velocidad inicial = 0 m / s

g = Aceleración debida a la gravedad = 9.81 m / s²

t = Tiempo de caída libre = 2.5 s

Por lo tanto;

v = 0 + 9.8 × 2.5 = 24.5 m / s

ii) El nivel que el cuerpo ha alcanzado en 2.5 segundos está dado por la relación

s = u · t + 1/2 · g · t²

= 0 × 2.5 + 1/2 × 9.81 × 2.5² = 30.656 m

iii) La altura restante = 120 - 30.656 = 89.344 m.

6 0
3 years ago
Students are asked to create roller coasters for marbles. Their goal is to design a coaster with the tallest possible hill that
ivann1987 [24]

Answer:

Kinetic Energy.

Explanation:

The movement of a roller coaster is accomplished by the conversion of potential energy to kinetic energy. The roller coaster cars gain potential energy as they are pulled to the top of the first hill. As the cars descend the potential energy is converted to kinetic energy.

3 0
2 years ago
A soccer player kicks a soccer ball initially at rest setting it in motion at a velocity of 30 m/s. If the ball has a mass of 0.
Alchen [17]

Answer:

 F= 600 N

Explanation:

Given that

Initial velocity ,u= 0 m/s

Final velocity ,v= 30 m/s

mass ,m = 0.5 kg

time ,t= 0.025 s

The change in the linear momentum is given as

ΔP= m (v - u)

ΔP= 0.5 ( 30 - 0 ) kg.m/s

ΔP= 15 kg.m/s

We know that from second law of Newtons

F=\dfrac{dP}{dt}

F=\dfrac{\Delta P}{t}

Now by putting the values

F=\dfrac{15}{0.025}\ N

F= 600 N

5 0
3 years ago
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