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Gemiola [76]
3 years ago
13

10 m/s in 10 3. A car accelerates from 0 m/s to 50 m/s in 10 seconds. What is the acceleration?

Physics
1 answer:
son4ous [18]3 years ago
3 0

Answer:

5ms⁻²

Explanation:

Given that,

Initial velocity of car (at t=0) u=0 m/s

Final velocity of car (after 10 sec) v=50 m/s

Time taken (t)= 10 sec.

acceleration(a)=?

now,

v = u + at

at = v-u

a=  (v-u) / t

a= (50-0) / 10

a = (50/10)

a=5 ms⁻²

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A 5.10 kgkg watermelon is dropped from rest from the roof of a 18.5 mm-tall building and feels no appreciable air resistance.
VARVARA [1.3K]

Work done is by the change in the potential energy of the system. The work done by gravity is 924.63 J.

<h3>What is the Kinetic Energy?</h3>
  • Potential energy in physics is the energy that an item retains as a result of its position in relation to other objects, internal tensions, electric charge, or other elements.
  • The gravitational potential energy of an object, which is based on its mass and distance from another object's center of mass, the elastic potential energy of an extended spring, and the electric potential energy of an electric charge in an electric field are examples of common types of potential energy. The joule, denoted by the letter J, is the energy unit in the International System of Units (SI).

Solution:

mass = 5.10 kg

height = 18.5 mm

We know that work done by the gravity on the watermelon is the change in the potential energy of the watermelon, therefore,

Work done due to gravity = change in the potential energy of the system

W = \Delta PE

W = mg (h₀ - h₁)

W = 5.10 × 9.8 × 18.5

W = 924.63 J

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7 0
2 years ago
at certain times the demand for electric energy is low and electric energy is used to pump water to a reservoir 45 m above the g
Readme [11.4K]

The mass of water that must be raised is 5.25\cdot 10^7 kg

Explanation:

Since the process is 70% efficiency, the power in output to the turbine can be written as

P_{out} = 0.70 P_{in}

where P_{in} is the power in input.

The power in input can be written as

P_{in} = \frac{W}{t}

where

W is the work done in lifting the water

t = 3 h = 10,800 s is the time elapsed

The work done in lifting the water is given by

W=mgh

where

m is the mass of water

g=9.8 m/s^2 is the acceleration of gravity

h = 45 m is the height at which the water is lifted

Combining the three equations together, we get:

P_{out} = 0.70 \frac{mgh}{t}

Where

P_{out} = 150 MW = 150\cdot 10^6 W

And solving for m, we find:

m=\frac{Pt}{0.70gh}=\frac{(1.50\cdot 10^6)(10800)}{(0.70)(9.8)(45)}=5.25\cdot 10^7 kg

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brainly.com/question/7956557

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3 0
3 years ago
Bodies weighing 1 kilogram and 5 kilograms lie on a smooth horizontal surface. If a traction force of 0.6 N acts on another 5 kg
natima [27]

0.6/5,1,5

so calculate it

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Which of these statements is true?
iogann1982 [59]
A and C is the correct one
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A train travels 600km in 4 hours. What is the speed of the train?
Bad White [126]

Answer: 150 miles per hour

Explanation:

600/4 just do 600÷4 on a calculator and you will get 150 miles.

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3 years ago
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