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AlladinOne [14]
2 years ago
5

Andy found these three ordered pairs for the equation y = 65x +250: (0, 250), (5,575), and (10,900). He graphed the ordered pair

s, and connected them with a line. State the range of this graph.

Mathematics
2 answers:
lakkis [162]2 years ago
4 0
<span>A, the highest Y value is 900 from the ordered pair (10,900) so as the least, the graph must go to 900. </span>
iVinArrow [24]2 years ago
4 0

Answer: The range of this graph is [250,500]

Step-by-step explanation:

Since we have given that

Andy found the equation:

y=65x+250

And he plot the three coordinates :

(0,250) , (5,575), and (10,900).

And he connected them with a line.

So, the range of this graph will be

[250, 500]

As the graph runs from 250 and ends at 500.

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anygoal [31]

Answer:

Step-by-step explanation:

H0 : μ = 46300

H1 : μ > 46300

α = 0.05

df = n - 1 = 45 - 1 = 44

Critical value for a one tailed t-test(since population standard deviation is not given).

Tcritical = 1.30

The test statistic :(xbar - μ) ÷ (s/sqrt(n))

The test statistic, t= (47800-46300) ÷ (5600√45)

t = 1500

t = 1500 / 834.79871

t = 1.797

The decision region :

Reject H0: if t value > critical value

1. 797 > 1.30

Tvalue > critical value ; We reject H0

Hence, there is sufficient evidence to conclude that cost has increased.

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2 years ago
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ValentinkaMS [17]
I believe the answer is 420
4 0
3 years ago
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iogann1982 [59]

Answer:

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Step-by-step explanation:

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6 0
3 years ago
If angle D is an acute angle and its tangent ratio is 1.055, then what is the measure of angle D to the nearest tenth of a degre
ArbitrLikvidat [17]

The measure of angle D to the nearest tenth of a degree is 47 degrees

<h3>Application of SOH CAH TOA</h3>

This theorem is used to determine the measure of sides and angles of a triangle.

According to the theorem

tan theta = opp/adj = 1.055

theta = arctan(1.055)

theta = 46.53 degrees

Hence the measure of angle D to the nearest tenth of a degree is 47 degrees

Learn more on SOH CAH TOA here: brainly.com/question/20734777

#SPJ1

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2 years ago
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andrew-mc [135]
So.. if you notice the picture below.. .the length is that much

thus    \bf A=lw\qquad \cfrac{1800-3w}{2}=l\implies 900-\cfrac{3w}{2}=l&#10;\\\\\\&#10;A=\left( 900-\cfrac{3w}{2} \right)w\implies A=900w-\cfrac{3w^2}{2}\implies A=900w-\cfrac{3}{2}w^2

take the derivative of A, zero it out, and then check the critica points for any maxima by using the first-derivative test

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