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max2010maxim [7]
3 years ago
10

A snowmobile has a mass of 540 kg. A constant force acts on it for 41 seconds. The snowmobile’s initial velocity is 9 m/s and fi

nal velocity is 34 m/s. What force is applied to the snowmobile during this time?
Physics
1 answer:
LekaFEV [45]3 years ago
5 0

Answer:

F = 329.27 N

Explanation:

given,

mass of snowmobile = 540 Kg

time = 41 s

intial velocity = 9 m/s

final velocity = 34 m/s

Force = ?

Force is equal to change in momentum per unit time

F = \dfrac{dp}{dt}

F = \dfrac{m(v_f-v_i)}{t}

F = \dfrac{540(34-9)}{41}

F = \dfrac{540\times 25}{41}

    F = 329.27 N

Force applied to the snowmobile is equal to F = 329.27 N

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Answer:

Part a)

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Part b)

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<u> </u><u>»</u><u> </u><u>Image</u><u> </u><u>distance</u><u> </u><u>:</u>

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{ \tt{ \frac{1}{v} +  \frac{1}{10} =  \frac{1}{5}   }} \\  \\  { \tt{ \frac{1}{v}  =  \frac{1}{10} }} \\  \\ { \tt{v = 10}} \\  \\ { \underline{ \underline{ \pmb{ \red{ \: image \: distance \: is \: 10 \: cm \:  \: }}}}}

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