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4 years ago

Which of the following statements about ionic bonds is false?

1 answer:

8 0

The answer is <span>B) the resulting compound cannot be dissolved in water. Ionic compounds are, in fact, very soluble in water. They are known to dissociate in aqueous solutions, producing ions or charged atoms. This makes aqueous solutions of ionic compounds good conductors of electricity. As solids, ionic compounds form salt crystals. They have high melting and boiling points due to the strong ionic bond that holds them.</span>

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ANSWER IF U LOVE UR MOM PLS

zalisa [80]

Answer:

yes

Explanation:

she loves me and i would die for her

8 0

3 years ago

Read 2 more answers

Calculate the ph of a buffer solution that contains 0.25 m benzoic acid (c6h5co2h) and 0.15 m sodium benzoate (c6h5coona). (ka =

zhannawk [14.2K]

Hello!

To solve this problem we'll use the Henderson-Hasselbach equation, but first we need the vale for the pKa of Benzoic acid, which is pKa= -log(Ka)=4,19

Now, we apply the equation as follows:

$pH=pKa + log ( \frac{[C_6H_5COONa]}{[C_6H_5COOH]} )=4,19+log( \frac{0,15M}{0,25M} )=3,97$

So, the pH of this solution of Sodium Benzoate and Benzoic Acid is 3,97

Have a nice day!

4 0

3 years ago

Read 2 more answers

What are the three parts of a nucleotide? an organic base, a protein, and a sugar an organic base, a phosphate group, and water

Katena32 [7]

Answer: an organic base, a phosphate group, and a sugar

Explanation:

A nucleotide is made up of 3 parts. We know a nucleotide is not made up of water so we are left with 2 choices. Nucleotides are made up of phosphate group, 5-carbon sugar, and nitrogenous base. The nitrogeneous base is typically adenine. The answer choice that matches this the closest is an organic base, a phosphate group, and a sugar.

The organic base is the nitrogeneous base and the sugar is the 5-carbon sugar.

8 0

4 years ago

A flame test of a colorless solution gives a bright yellow color. When reacted with AgNO3 a white precipitate forms that dissolv

hichkok12 [17]

Answer:

The compound is Na2CO3

Explanation:

A flame test of a colorless solution gives a bright yellow color. The yellow color shows the presence of Sodium.

NaX + AgNO3 → AgX + NaNO3

When reacted with AgNO3 a white precipitate.

AgX + HNO3 → AgNO3 + H2O + CO2

A white precipitate will be formed when AgNO3 reacts with Sodium Chloride (NaCl) or Sodium carbonate(Na2CO3). (Also NaF, Na3PO4 are possible).

When HCL is added to the unknown solution, bubbles form.

Forming bubbles means that there is formed CO2 (and H20)

Na2X + 2HCl → 2NaCl + H2O + CO2

To form CO2 there is carbon needed

This shows that X is CO3 and the compound is Na2CO3

<u>To control:</u>

Na2CO3 + AgNO3 → Ag2CO3 + NaNO3

⇒Ag2Co3 is the white precipitate formed

This precipitate Ag2CO3 + HNO3 will disolve in AgNO3, CO2 and H2O

When Na2CO3 reacts with HCl there is formed NaCL together with bubbles ( which is CO2 and H2O).

The compound is Na2CO3

3 0

3 years ago

You are given two aqueous solutions with different ionic solutes (Solution A and Solution B). What if you are told that Solution

klio [65]

Answer:

Yes, it is possible. Let us consider an example of two solutions, that is, solution A having 20 percent mass RbCl (rubidium chloride) and solution B is having 15 percent by mass NaCl or sodium chloride.

It is found that solution A is having more concentration in comparison to solution B in terms of mass percent. The formula for mass percent is,

% by mass = mass of solute/mass of solution * 100

Now the formula for molality is,

Molality = weight of solute/molecular weight of solute * 1000/ weight of solvent in grams

Now molality of solution A is,

m = 20/121 * 1000/80 (molecular weight of RbCl is 121 grams per mole)

m = 2.07

Now the molality of solution B is,

m = 15/58.5 * 1000/85

m = 3.02

Therefore, in terms of molality, the solution B is having greater concentration (3.02) in comparison to solution A (2.07).

5 0

3 years ago