Answer:
The balance equation is
→ 
Explanation:
first, we have to make sure that the atoms are balanced
→ 
→ 
then we proceed to balance charges of each half-reaction
→
→ 
Now we multiply the half-reactions to match the number of electrons in each one
( → )x2
( → )x3
and now we do the sum of the half-reactions
2
→ 2
→ 3 
→
note: the only atom that needed to be balanced was I
Answer:
ΔG° = -533.64 kJ
Explanation:
Let's consider the following reaction.
Hg₂Cl₂(s) ⇄ Hg₂²⁺(aq) + 2 Cl⁻(aq)
The standard Gibbs free energy (ΔG°) can be calculated using the following expression:
ΔG° = ∑np × ΔG°f(products) - ∑nr × ΔG°f(reactants)
where,
ni are the moles of reactants and products
ΔG°f(i) are the standard Gibbs free energies of formation of reactants and products
ΔG° = 1 mol × ΔG°f(Hg₂²⁺) + 2 mol × ΔG°f(Cl⁻) - 1 mol × ΔG°f(Hg₂Cl₂)
ΔG° = 1 mol × 148.85 kJ/mol + 2 mol × (-182.43 kJ/mol) - 1 mol × (-317.63 kJ/mol)
ΔG° = -533.64 kJ
Na = +1
H = +1
O = -2
Total charge is 0:
1 + 1 + C + 3 x -2 = 0
C = 4
Answer:
108.3kPa
Explanation:
Given parameters:
Initial temperature = 76k
Initial pressure = 78.4kPa
Final temperature = 105k
Unknown:
Final or new pressure = ?
Solution:
To solve this problem, we apply the combined gas law:
= 
T1 = 76k
P1 = 78.4kPa
T2 = 105k
= 
P2 = 108.3atm
The balanced equation is 2H2+O2=2H2O i think
