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Vilka [71]
3 years ago
7

ANSWER IF U LOVE UR MOM PLS

Chemistry
2 answers:
zalisa [80]3 years ago
8 0

Answer:

yes

Explanation:

she loves me and i would die for her

erastova [34]3 years ago
4 0

Answer: I think its B

Explanation:

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How many grams of potassium chloride are needed to make 100 ml of a solution containing 250 mosmol/l? (m.w. of potassium is 39 a
LUCKY_DIMON [66]
In dilute solutions, the unit osmolarity is being used. It usually has units milliosmols per liter of solution or mOsmol/L. An osmole defines the number of moles of the solute that would have an effect on the osmotic pressure of the solution. Osmolarity is calculated by the product of the molarity and the number of particles in the solution which is 2 for potassium chloride. We calculate as follows:
Osmolarity = molarity (# of particles)250 mosmol/L ( 1 osmol / 1000 osmol) = x moles / .100 L (2)
x moles = 0.0125 mol KCl
mass KCl = 0.0125 mol KCl ( 39 + 35.5 g/mol) = 0.93125 g KCl
5 0
3 years ago
The density of liquid mercury is 13.6 g/mL. What is its density in units of lb/in​3​? (2.5 cm+1 in., 2.205 lbs= 1 kg., 1000 g =1
shusha [124]

Answer:

Density, \rho=0.49\ lb/in^3

Explanation:

It is given that the density of liquid mercury is 13.6 g/mL. We need to convert the density into lb/in³.

We know that,

2.205 lbs= 1 kg

1 g = 0.0022 lb

1 mL = 0.0610 in³

13.6\ \dfrac{g}{mL}=13.6\times \dfrac{0.0022\ lb}{0.0610\ in^3}\\\\=0.49\ lb/in^3

So, the density of liquid mercury is 0.49\ lb/in^3.

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It stands for engineering science and mechanics
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