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2 years ago

10

an object with a mass of 1.5 kg changes its velocity from 15 m/s to 22 m/s during a time interval of 3.5 seconds. what impulse w

as delivered to the object?

2 answers:

professor190 [17]2 years ago

8 0

Answer:

B

Explanation:

just did on edgen

natulia [17]2 years ago

6 0

Impulse is the change in momentum

J = 1.5 kg(22 m/s - 15 m/s) = 10.5 kg-m/s

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A scuba diver is sitting on a boat while waiting to go on a dive and sees light reflected from the water's surface. At what angl

LUCKY_DIMON [66]

Answer:

θ_p = 53.0º

Explanation:

For reflection polarization occurs when a beam is reflected at the interface between two means, the polarization in total when the angle between the reflected and the transmitted beam is 90º

Let's write the transmission equation

n1 sin θ₁ = ne sin θ₂

The angle to normal (vertcal) is

180 = θ2 + 90 + θ_p

θ₂ = 90 - θ_p

Where θ₂ is the angle of the transmitted ray θ_p is the angle of the reflected polarized ray

We replace

n1 sin θ_p = n2 sin (90 - θ_p)

Let's use the trigonometry relationship

Sin (90- θ_p) = sin 90 cos θ_p - cos 90 sin θ_p = cos θ_p

In the law of reflection incident angle equals reflected angle,

ni sin θ_p = ns cos θ_p

n₂ / n₁ = sin θ_p / cos θ_p

n₂ / n₁ = tan θ_p

θ_p = tan⁻¹ (n₂ / n₁)

Now we can calculate it

The refractive index of air is 1 (n1 = 1) the refractive index of seawater varies between 1.33 and 1.40 depending on the amount of salts dissolved in the water

n₂ = 1.33

θ_p = tan⁻¹ (1.33 / 1)

θ_p = 53.0º

n₂ = 1.40

θ_p = tan⁻¹ (1.40 / 1)

Tep = 54.5º

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2 years ago

How is fission used to produce electricity? a. the heat generated from the fission reaction is used to boil water, which rises a

denis-greek [22]

According to the research, the correct option is a. The heat generated from the fission reaction is used to boil water, which rises and spins a turbine.

<h3>How is fision used to produce electricity?</h3>

In fusion, two atoms come together to form a larger one, releasing enormous amounts of energy in the process, this is used by generators to produce electricity.

As a result of nuclear fusion, large amounts of heat are generated that are used to produce pressurized steam, which allows mechanical energy to be obtained to start up electric power generators.

Therefore, we can conclude that according to the research, the correct option is a. The heat generated from the fission reaction is used to boil water, which rises and spins a turbine.

Learn more about fision reaction here: brainly.com/question/13207914

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1 year ago

Will an object with a density of 1.05 g/ml float or sink in water? Explain.

WINSTONCH [101]

It will sink because it is heavier. The density of water 1.00 g/ml

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3 years ago

Suppose you are standing on top of a hemisphere of radius r and you kick a soccer ball horizontally such that it has velocity v.

Ksivusya [100]

$|v| =\sqrt{ G \cdot M / r}$ , where

$M$ the mass of the planet, and
$G$ the universal gravitation constant.

Explanation:

Minimizing the initial velocity of the soccer ball would minimize the amount of mechanical energy it has. It shall maintain a minimal gravitational potential possible at all time. It should therefore stay to the ground as close as possible. An elliptical trajectory would thus be unfavorable; the ball shall maintain a uniform circular motion as it orbits the planet.

<em>Equation 1</em> (see below) relates net force the object experiences, $\Sigma F$ to its orbit velocity $v$ and its mass $m$ required for it to stay in orbit :

$\Sigma F = m \cdot v^{2} / r$ <em>(equation 1)</em>

The soccer ball shall experiences a combination of gravitational pull and air resistance (if any) as it orbits the planet. Assuming negligible air resistance, the net force $\Sigma F$ acting on the soccer ball shall equal to its weight, $W = m \cdot g$ where $g$ the gravitational acceleration constant. Thus

$\Sigma F = W = m \cdot g$ <em>(equation 2)</em>

Substitute equation 2 to the left hand side of <em>equation 1</em> and solve for $v$ ; note how the mass of the soccer ball, $m$ , cancels out:

$m \cdot g = \Sigma F = m \cdot v^{2} / r \\ v^{2} = g \cdot r \\ |v| = \sqrt{g \cdot r} \; (|v| \ge 0)$ <em>(equation 3)</em>

<em>Equation 4 </em> gives the value of gravitational acceleration, $g$ , a point of negligible mass experiences at a distance $r$ from a planet of mass $M$ (assuming no other stellar object were present)

$g = G \cdot M/ r^{2}$ <em>(equation 4)</em>

where the universal gravitation <em>constant</em> $G = 6.67408 \times 10^{-11} \cdot \text{m}^{3} \cdot \text{kg}^{-1} \cdot \text{s}^{-2}$

Thus

$\begin{array}{lll}|v| &=& \sqrt{g \cdot r}\\ & =&\sqrt{ G \cdot M / r}\end{array}$

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3 years ago

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11Alexandr11 [23.1K]

Answer:

The force each one experienced

Explanation:

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2 years ago