Answer:
v = 1 m/s
Explanation:
from the principle of conservation of momentum, we have following relation
initial momentum = final momentum
where
m1 = 1.14 kg
v1 = 2.0 m/s
m2 = 1.14 kg
v2 = 0 m/s
putting all value in the above equation
v = 1 m/s
How much work did the movers do (horizontally) pushing a 46.0-kgkg crate 10.5 mm across a rough floor without acceleration, if t
1 answer:
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Answer:
The answer to your question is 636.6 ft
Explanation:
Data
base = 425 ft
angle = 39°
See the picture below
1.- Divide the triangle to get two right triangles.
Now the superior angle will measure 19.5° and the opposite side will measure 212.5 ft
2.- Use the trigonometric function sine to find the hypotenuse
sin 19.5 = 212.5/hyp
solve for hyp
hyp = 212.5 / sin 19.5
Result
hyp = 212.5/ 0.333
hyp = 636.6 ft
