Answer:
frequency of the sound = f = 1,030.3 Hz
phase difference = Φ = 229.09°
Explanation:
Step 1: Given data:
Xini = 0.540m
Xfin = 0.870m
v = 340m/s
Step 2: frequency of the sound (f)
f = v / λ
λ = Xfin - Xini = 0.870 - 0.540 = 0.33
f = 340 / 0.33
f = 1,030.3 Hz
Step 3: phase difference
phase difference = Φ
Φ = (2π/λ)*(Xini - λ) = (2π/0.33)* (0.540-0.33) = 19.04*0.21 = 3.9984
Φ = 3.9984 rad * (360°/2π rad)
Φ = 229.09°
Hope this helps!
Answer:
The power expended by the car during the acceleration is 116.38KW
Explanation:
Power is a term that defines the rate at which energy is expended whenever work is done.
Power can be given as Force X velocity.
Force can be found using the formula:
F = mass X acceleration.
In this case,
F = 1100kg X 4.6m/s2
F = 5060 N
The final velocity, v of the car can be obtained from this formula:
v = u+ at
U = initial velocity = 0 (since the car started from rest)
a = acceleration = 4.6m/s2
t = time = 5 seconds
v = 0 + 4.6 X 5 = 23 m/s
Therefore, the power expended is 5060N X 23m/s=116,380W
The power expended by the car during the acceleration is 116.38KW
Answer:
option a
Explanation:
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