Two 110 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car Z at –10 m/s when t
hey collide head–on. If the resulting velocity of Car A after the collision is –10 m/s, what is the velocity of Car Z after the collision?
A. -10 m/s
B. -8 m/s
C. 8 m/s
D. 10 m/s
A. -10 m/s
B. -8 m/s
C. 8 m/s
D. 10 m/s
1 answer:
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Answer:
Yes, correct
Explanation:
velocity, v = 470 m/s
radius, r = 0.15 m
The radial acceleration is the centripetal acceleration which always acts towards the centre of the circular centrifuge.
The formula for the centripetal acceleration is given by
a = 1472666.667
a = 150272.1 g
According to the question, we can get the acceleration as mentioned. So the claim is correct.
(a). The car's average velocity between t = 1.0s to t = 1.5s will be -
(b). The car's acceleration at t = 1.5s will be -
(c). Car's speed is increasing with time.
We have a a remote controlled toy car that starts from rest and begins to accelerate in a straight line.
We have to determine -
- The car's average velocity (in m/s) in the interval between -
t = 1.0 s to t = 1.5 s.
- The car's acceleration at t = 1.5 s.
- Determining whether car's speed increasing or decreasing with time.
The rate of change of velocity with respect to time is called Acceleration. Mathematically -
According to the question, we have the following data for the Car -
t = 0s → x = 0m
t = 0.5s → x = 0.1m
t = 1.0s → x = 0.4m
t = 1.5s → x = 0.9m
t = 2.0s → x = 1.6m
PART - A
The car's average velocity between t = 1.0s to t = 1.5s will be -
PART - B
Velocity at t = 1.5 s will be -
The car's acceleration at t = 1.5s will be -
PART - C
Since, the acceleration of the car is positive, this means that the car is accelerating in the forward direction. Hence, its speed is increasing with time.
[ The following data was missing in your answer. The complete question would include this data also -
t = 0s → x = 0m
t = 0.5s → x = 0.1m
t = 1.0s → x = 0.4m
t = 1.5s → x = 0.9m
t = 2.0s → x = 1.6m ]
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