Two 110 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car Z at –10 m/s when t
hey collide head–on. If the resulting velocity of Car A after the collision is –10 m/s, what is the velocity of Car Z after the collision?
A. -10 m/s
B. -8 m/s
C. 8 m/s
D. 10 m/s
A. -10 m/s
B. -8 m/s
C. 8 m/s
D. 10 m/s
1 answer:
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Answer:43.34 m
Explanation:
Given
acceleration(a)
Initial Velocity(u)=0 m/s
After 6 s fuel runs out
Velocity after 6 s
v=u+at
After this object will start moving under gravity
height reached in first 6 s
s=36 m
After fuel run out distance traveled in upward direction is
here v=0
u=12 m/s
Answer:
Kinetic energy of bigger rock will be more than that of smaller one.
Explanation:
Kinetic energy of the rock is given by,
Kinetic energy =
As velocity of both the rocks are same. Thus, kinetic energy is directly proportional to the mass of the rock
Kinetic energy ∝ mass
So, For greater mass kinetic energy will be greater and for smaller mass kinetic energy will be smaller.
Hence, Kinetic energy of bigger rock will be more than that of smaller one.