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VashaNatasha [74]
3 years ago
5

Two 110 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car Z at –10 m/s when t

hey collide head–on. If the resulting velocity of Car A after the collision is –10 m/s, what is the velocity of Car Z after the collision?
A. -10 m/s
B. -8 m/s
C. 8 m/s
D. 10 m/s

Physics
1 answer:
julsineya [31]3 years ago
6 0

This is a conservation of momentum problem! Here's how to do it:

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How much heat is needed to change the temperature of 3 grams of gold (c = 0.129 ) from 21°C to 363°C? The answer is expressed to
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The correct answer to the question is : B) 132 Joules.

EXPLANATION :

As per the question, the mass of the gold m = 3 gram.

The initial temperature of the gold T = 21 degree celsius.

The final temperature of the gold  T' = 363 degree celsius.

Hence, the change in temperature  dT = T' - T

                                                          = 363 - 21 degree celsius

                                                          = 342 degree celsius.

The specific heat of the gold is given as c = 0.129\ J/g^0C

We are asked to calculate the heat required ( dQ ) to raise the temperature of gold.

The heat required for this is calculated as -

                                   dQ = mcDT

                                         = 3 × 342 × 0.129 J

                                         = 132.354 J

                                         ≈ 132 J

Hence, the correct answer is 132 J.

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3 years ago
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A kickoff sends a football with an initial velocity of 25 m/s at an angle of 50
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Answer:

The x-component of the velocity is 16.07 m/s

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Explanation:

Given;

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The y-component of the velocity (vertical component) is given as;

V_y = Vsin(50^0)\\\\V_y = 25 \ m/s \ \ \times \ \ 0.766\\\\V_y = 19.15 \ m/s

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Explanation:

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