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VashaNatasha [74]
3 years ago
5

Two 110 kg bumper cars are moving toward each other in opposite directions. Car A is moving at 8 m/s and Car Z at –10 m/s when t

hey collide head–on. If the resulting velocity of Car A after the collision is –10 m/s, what is the velocity of Car Z after the collision?
A. -10 m/s
B. -8 m/s
C. 8 m/s
D. 10 m/s

Physics
1 answer:
julsineya [31]3 years ago
6 0

This is a conservation of momentum problem! Here's how to do it:

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Answer:

625000 N/ m

Explanation:

m= 20 kg

v= 30 m/s

x= 12 cm

k = ?

Here when the mass when hits at spring its speed is

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Finally it comes to rest after compressing for 12 cm

i-e Vf = 0 m/s

Distance= S= 12 cm = 0.12 m

using

2aS= Vf2 - Vi2

==> 2a ×0.12 = o- 30 × 30

==> a = 900 ÷ 0.24 = 3750 m/sec2

Now we know;

F = ma

F= -Kx

==> ma= -kx

==> 20 × 3750 = -K × 0.12

==> k = 625000 N/ m

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Explanation:

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Answer:

33.33 m/sec

Explanation:

A baseball travels 200 metes in 6 seconds,

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