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4 years ago

HSiCl3+H2O=H10Si10O15+HCl

Chemistry

1 answer:

tiny-mole [99]4 years ago

5 0

10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl

Explanation:

Step 1: To make Si equal on both sides. put 10 in front of HSiCl3

10 HSiCl3+ H2O →H10Si10O15+ HCl

Step 2: By putting 30 in front of HCl, Cl can be balanced

10 HSiCl3+ H2O →H10Si10O15+ 30 HCl

Step 3: Now, balance O by putting 15 in front of H2O

10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl

Hence the balanced equation is:

10 HSiCl3+ 15 H2O→H10Si10O15+ 30 HCl

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The reaction that will probably power the first commercial fusion reactor is:3 0 H + 2 1 H image from custom entry tool4 2 He +

Lelechka [254]

Answer:

2.8087*10^-12 kJ per mole of reaction (2.8087*10^-12 kJ/mol).

Explanation:

To calculate the energy produced, we need to write a balanced equation for the reaction and determine the change in the masses of the reactants and products. Afterward, we can use the energy equation to determine the energy produced. The balanced equation for the nuclear reaction is shown below:

³₁H + ²₁H ⇒⁴₂He + ¹₀n

The masses of atoms are ³₁H is 3.01605 amu, ²₁H is 2.0140 amu, ⁴₂He is 4.00260 amu, and ¹₀n is 1.008665 amu.

change in mass Δm = (3.01605+2.0140) - (4.00260+1.008665) = 0.0188 amu

Energy produced, E = m*C^2

C is the speed of light = 3*10^8 m/s and 1 amu = 1.66*10^-27 kg

Therefore:

E = 0.0188*1.66*10^-27 * (3*10^8)^2 = 2.8087*10^-12 kJ per mole of reaction.

Therefore, in scientific notation, the energy released is 2.8087*10^-12 kJ/mol

7 0

3 years ago

WHAT IS THE ABILITY OF A SUBSTANCE TO BE DISSOLVED

siniylev [52]

Answer:

Solubility

Explanation:

8 0

3 years ago

Help please I don't understand

e-lub [12.9K]

Try looking at the question a little bit harder.

3 0

3 years ago

Give the name and formula of the compound formed from the following elements: a) Sodium and nitrogen b) Oxygen and strontium c)

elena-s [515]

Answer: a) Sodium and nitrogen : $NaN_3$ : sodium nitride.

b) Oxygen and strontium : $SrO$ : strontium oxide.

c) Aluminum and chlorine : $AlCl_3$ : aluminium chloride.

d) Cesium and bromine : $CsBr$ : cesium bromide.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

a) Sodium and nitrogen : Here sodium is having an oxidation state of +1 called as $Na^{+}$ cation and nitrogen forms an anion $N^{3-}$ with oxidation state of -3. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $NaN_3$ named as sodium nitride.

b) Oxygen and strontium : Here strontium is having an oxidation state of +2 called as $Sr^{+}$ cation and oxygen forms an anion $O^{2-}$ with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $SrO$ named as strontium oxide.

c) Aluminum and chlorine : Here aluminium is having an oxidation state of +3 called as $Al^{3+}$ cation and chlorine forms an anion $Cl^{-}$ with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $AlCl_3$ named as aluminium chloride.

d) Cesium and bromine : Here cesium is having an oxidation state of +1 called as $Cs^{+}$ cation and bromine forms an anion $Br^{-}$ with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $CsBr$ named as cesium bromide.

7 0

3 years ago

Electrons are always shared evenly during covalent bonding.<br> O True<br> False

neonofarm [45]

Answer:

False

Explanation:

There are two types of covalent bonding: polar covalent boding and nonpolar covalent bonding. During polar covalent bonding, the electrons are not shared evenly. This is due to the electronegativity differences between the two atoms. During nonpolar covalent bonding, the electrons are shared evenly.

8 0

2 years ago