Answer:
Carbon dioxide
Explanation:
Neither helium nor carbon dioxide has a molecular dipole, so their strongest van der Waals attractive forces are London forces.
Helium is a small spherical atom with only a two electrons, so its atoms have quite weak attractions to each other.
CO₂ is a large linear molecule. It has more electrons than helium, so the attractive forces are greater. Furthermore, the molecules can align themselves compactly side-by-side and maximize the attractions (see below).
For example. CO₂ becomes a solid at -78 °C, but helium must be cooled to -272 °C to make it freeze (that's just 1 °C above absolute zero).
Answer:
Bonds are polar when one element in a compound is more electronegative than the other. This creates a dipole in the molecule where one end of the molecule is partially positive and one end is partially negative
Explanation:
I believe D. because all the organisms that live in a lake can be a bunch of living things that would be considered a population and not a species. I canceled out B. from the get go because, I don’t believe non living organisms can be in a population ?
Please get back to me if I’m right or wrong :)
Answer:
Decomposition
Explanation:
A decomposition reaction is a type of reaction in which a compound is broken down into its constituent elements sometimes under the influence of heat.
When iron (III) hydroxide is heated,new products are formed according to the equation; 2Fe(OH)3 -----------> Fe2O3 + 3H2O.
This is a thermal decomposition reaction.
Answer: The boiling point of a 3.70 m solution of phenol in benzene is 
Explanation:
Elevation in boiling point:

where,
= change in boiling point
i= vant hoff factor = 1 (for benzene which is a non electrolyte )
= boiling point constant = 
m = molality = 3.70



Thus the boiling point of a 3.70 m solution of phenol in benzene is 