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3 years ago

In 3 seconds, a wave generator produces 15 pulses that spread over a distance of 45 centimeters. Calculate its velocity.

1 answer:

6 0

We don't even need to know how many pulses were produced
in those 3 seconds.

The beginning of the first pulse took 3 seconds to travel
45 centimeters from the generator.

Its speed is (45 cm) / (3 sec) = 15 cm/sec.

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PLEASE PLEASE HELP ME!

Vlad1618 [11]

B: heat is transferred as thermal energy by the interaction of moving particles

6 0

3 years ago

Which of the following can only be a situation of increasing temperature?

Papessa [141]

Increasing the temperature causes an increase in the average kinetic energy of the particles of a material.

<h3>What is average kinetic energy of particles?</h3>

The average kinetic energy of particles is the energy possessed by particles due to their constant motion.

The constant motion of particles occurs due to the energy acquired by the particles, when the temperature of the particles increases, the average kinetic energy increases which in turn increases the speed of the particles.

Thus, we can conclude that, increasing the temperature causes an increase in the average kinetic energy of the particles of a material.

Learn more about average kinetic energy here: brainly.com/question/9078768

5 0

3 years ago

Parallel rays of monochromatic light with wavelength 571nm illuminate two identical slits and produce an interference pattern on

Natasha2012 [34]

Answer:

$8.8\times 10^{-6} W/m^2$

Explanation:

We are given that

Wavelength, $\lambda=571 nm=571\times 10^{-9} m$

$1 nm=10^{-9} m$

R=75 cm= $\frac{75}{100}=0.75 m$

1 m=100 cm

$d=0.640 mm=0.64\times 10^{-3} m$

$1 mm=10^{-3} m$

$a=0.434 mm=0.434\times 10^{-3} m$

$y=0.830 mm=0.830\times 10^{-3} m$

$I_0=5.00\times 10^{-4}W/m^2$

$tan\theta=\frac{y}{R}$

$\theta=\frac{0.830\times 10^{-3}}{0.75\times 10^{-2}}$

$\theta=1.1\times 10^{-3}rad$

$tan\theta\approx \theta$

Because $\theta$ is small.

$\phi=\frac{2\pi dsin\theta}{\lambda}$

$\sin\theta\approx \theta$ ,

Therefore

$\phi=\frac{2\times\pi\times 0.64\times 10^{-3}\times 1.1\times 10^{-3}}{571\times 10^{-9}}$

$\phi=7.74 rad$

$\beta=\frac{2\pi a\theta}{\lambda}$

$\beta=5.3 rad$

$I=I_0cos^2(\frac{\phi}{2})(\frac{sin\frac{\beta}{2}}{\frac{\beta}{2}})^2$

$I=5\times 10^{-4}cos^2(\frac{7.74}{2})(\frac{sin\frac{5.3}{2}}{\frac{5.3}{2}})^2$

$I=8.8\times 10^{-6} W/m^2$

6 0

3 years ago

you throw an object straight up at 15m/s. how fast is it going when it gets back to the height from which you threw it?

laiz [17]

At the same speed because it will slow down as it approaches the peak then speed up as it goes down again

it will be going 15m/s when it gets to the same height if we neglect air resistance and the object doesn't hit something

8 0

3 years ago

The mass of a sample of iron is 31.5 g. The volume is 5 cm3. What is the density of iron in g/cm3?

ELEN [110]

Answer : 6.3 g/cm3
Step by step explanation:
Density = mass/volume

3 0

3 years ago